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" From half the sum of the three sides, subtract each side severally; multiply the half sum, and the three remainders together, and the square root of the product will be the area required. "
Principles of Architecture: Comprising Fundamental Rules of the Art, with ... - Side 92
av Peter Nicholson, Joseph Gwilt - 1848 - 280 sider
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The Decorator's assistant

...sides subtract each side severally, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. 1. What will be the area of the triangle AB c, the side of which, AB, is 50 ft., B c 40 ft., and AC...
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Principles of geometry, mensuration, trigonometry, land-surveying, and ...

Thomas Tate (mathematical master.) - 1848
...Ans. 68-736. 3. PROBLEM. To find the area of a triangle, given the three sides. RULE. From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders continually together, and the square root of the last product will be the area of the triangle. (See...
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A Treatise on Surveying and Civil Engineering, Wherein Everything that is ...

P. O'Shaughnessy (Civil engineer) - 1848 - 98 sider
...Prob. 5. To find the area of a plain triangle when the three sides are given. Rule. — From half the sum of the three sides subtract each side severally. Multiply the half sum and the three remainders continually together, the square root of the product will be the area. Demonstration. — Let ABC figure...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - 1848 - 288 sider
...the sum of the four sides subtract each side severally; then multiply the four remainders continualiy together, and the square root of the product will be the area. 2. Required the area of a trapezium who?e diagonal is ?0.5, and the two perpendiculars 2-l.~, and 30.1....
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The millwright & engineer's pocket companion

William Templeton (engineer.) - 1848
...sides subtract each side separately, and multiply the three remainders so obtained and the half sum together, and the square root of the product will be the area. EXAMPLE 1. — Required the area of a triangle ABC, whose base AB = 16.5, and perpendicular DC = 10.25....
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An introductory treatise on mensuration, in theory and practice

John Radford Young - 1850 - 12 sider
...IV. — To find the area of a triangle when all its three sides are given. RULE. — From half the sum of the three sides subtract each side severally....remainders together, and the square root of the product of these four quantities will be the area. The theoretical principles upon which this rule is founded...
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The Practical Model Calculator: For the Engineer, Mechanic, Machinist ...

Oliver Byrne - 1851 - 293 sider
...= area required. To find the area of a triangle whose three sides only are given. — From half the sum of the three sides subtract each side severally. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required Required the area...
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ENGINEERS AND MECHANICS POCKET BOOK

CHAS. H. HASWELL - 1853
...sides subtract each side separately ; then multiply the half sum and the three remainders continually together, and the square root of the product will be the area. To find the Length of one side of a Right-angled Triangle, when the Length of the other two sides are...
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The Elements of Plane and Spherical Trigonometry

John Hind - 1855 - 328 sider
...length will be : From half the sum of the sides, subtract each side separately; multiply the half-sum and the three remainders together, and the square root of the product will be the area. Ex. Let it be required to find the area of the triangle, whose three sides are 18, 24, and 30 yards....
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The Mechanic's, Machinist's, and Engineer's Practical Book of Reference ...

Charles William Hackley - 1855 - 504 sider
...sides subtract each side separately, and multiply the three remainders so obtained and the half sum together, and the square root of the product will be the area. EXAMPLE 1. Required the area of a triangle ABC, whose busa AB =; 16-5, and perpendicular DC = 10-25....
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