| Dennis M'Curdy - 1846 - 138 sider
...any angle with AB. In AC take a point D, and make AC the same multiple of AD that AB is of the part **to be cut off from it: join BC, and draw DE parallel to it** ; AE is the part required. Because ED is parallel to BC, a side of the triangle ABC (a), CD : DA :... | |
| Royal Military Academy, Woolwich - 1853
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC ; as CD is to DA, so is... | |
| Euclides - 1853 - 147 sider
...making any angle with ab; and in a С take any point d, and take a С the same multiple of ad, that a Ь **is of the part which is to be cut off from it : join,** b С, and draw de parallel to it : then ae is the part required to be cut off. Because ed is parallel... | |
| Euclides - 1855
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...draw DE parallel to it : then AE is the part required** tobecut of. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle ABC ; as... | |
| John Playfair - 1855 - 318 sider
...and in AC take any point 1), and take AC such that it shall contain AD, as oft as AB is to contain **the part, which is to be cut off from it ; join BC, and** dniw DE parallel to it: then AK is the part required to be cut off. triangle ABC, viz. to BC, CD :... | |
| Euclides - 1860
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD that AB is of the part which is to...to it; then AE is the part required to be cut off.** (Dem.) Because ED is parallel to one of the sides of the triangle ABC, namely, to BC ; CD is to DA... | |
| Eucleides - 1860
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...to it .then AE is the part required to be cut off.** VI. 2. 6) V. 18. v. D. DEMONSTRATION. Because ED is parallel to BC, one of the sides of the triangle... | |
| Robert Potts - 1860 - 361 sider
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to** CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
| Euclides - 1863
...angle BAC with AB. In AC take any point D, and make AC the same multiple of AD that AB is of the part **to be cut off from it. Join BC, and draw DE parallel to** CB. The A part AE is the part required to be cut off from AB. PEOP. IX. (PEOELEM.)—From a gicen straight... | |
| Euclides - 1864
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to** CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
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