 | George Bruce Halsted - 1886 - 394 sider
...find the area of a triangle. 319 808. Given, the three sides, to find the area of a triangle. RULE. From half the sum of the three sides subtract each side separately ; mult1ply together the half-sum and the three remainders. The square root of tltis product is the... | |
 | Andrew Jackson Rickoff - 1886 - 688 sider
...following rule is sometimes necessary : When the three sides of a triangle are given, to find the area : From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | Edward Richard Shaw - 1887 - 360 sider
...— i 244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | Edward Richard Shaw - 1887 - 488 sider
...* = 244. That which has length and breadth only. 245. Multiply the base by half the altitude. 246. From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | W. V. Wright - 1887 - 76 sider
...Divide the circumference by 3.14159. When the three sides of a triangle are given, to find the area : From• half the sum of the three sides subtract each side separately. Multiply the half-sum and the three remainders together, and extract the square root of the product.... | |
 | Christian Brothers - 1888 - 484 sider
...2? 52 — 39 = 13 52 — 40 = 12 52 x 27 x 13 x 12 = 219024 Area = -v/219024 = 468 sq. yd. RULE. — From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together; and the square root of the continued... | |
 | Andrew Jackson Rickoff - 1888 - 464 sider
...following rule is sometimes necessary : When the three sides of a triangle are given, to find the area: From half the sum of the three sides subtract each side separately. Multiply the half sum and the three remainders together, and extract the square root of the product.... | |
 | Charles Scott Venable - 1888 - 402 sider
...equals half of the product of either side by the perpendicular to it from the opposite vertex; or, from half the sum of the three sides subtract each side separately ; multiply together the half sum and the three remainders ; and the square root of the product is the... | |
 | Thomas A. Rice - 1889 - 364 sider
...Multiply three sides together. 6. To find area of triangle. — Multiply base by half the altitude. Or, from half the sum of the three sides subtract each side separately ; multiply the half sum by the three remainders, and extract square root of product. 7. To find area... | |
 | Horatio Nelson Robinson - 1892 - 428 sider
...= 60 ; 60 - 30 = 30 ; 60 - 40 = 20; 60 - 50 = 10. \X60~x30 x 20 x 10 = 600 sq. ft., area. RULE. — From half the sum of the three sides subtract each side separately; multiply the half-sum and the three remainders together; the square root of the product is the area.... | |
| |
RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 
