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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14.
An Introduction to Algebra, with Notes and Observations: Designed for the ... - Side 136
av John Bonnycastle - 1829 - 312 sider
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## Elements of Arithmetic, Algebra, and Geometry

George Lees - 1826
...— — = - — 4, the numerator. The •* Jc 2 4 fraction sought is therefore -. EXERCISES. Ex. 1. It is required to divide the number 24 into two such parts, that twice the greater may exceed three times the less by 3. Ans. 15 and 9. Ex. 2. What number is that,...
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## An Introduction to Algebra: Being the First Part of a Course of Mathematics ...

Jeremiah Day - 1827 - 332 sider
...whose difference, sum, and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares, as 3 to 10. Ans. 18 and 6. 13. In a mixture of rum and brandy, the difference...
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## Algebraic exercises, Volum 1

Henry Ottley - 1828
...x2— 60z +900=36. (Extract the root,) and x— 30 =6, or x=36. Ans. the numbers are 24 and 36. 3. Divide the number 24 into two such parts, that their product shall be 35 times their difference. Let x=one part, then 24— x= the other, and 24 — 2x=the difference. Then...
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## Elements of Algebra: Tr. from the French of M. Bourdon, for the Use ..., Volum 1

Bourdon (M., Louis Pierre Marie) - 1831 - 389 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2Q. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 21. The sum of two numbers is 8, and the...
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## Elements of Algebra: Tr. from the French of M.Bourdon. Revised and Adapted ...

Charles Davies - 1835 - 353 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the...
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## Elements of Algebra

1838 - 358 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the...
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## First Lessons in Algebra: Embracing the Elements of the Science

Charles Davies - 1839 - 252 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their dif1 ference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the...
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## An Elementary Treatise on Algebra, in Theory and Practice: With Attempts to ...

John D. Williams - 1840 - 605 sider
...then by the question (10— x)x=2l, or я?— 10z= — 21. Whence ж=5±(25— 21)= б±2=7 or 3. 13. It is required to divide the number 24 into two such...product shall be equal to 35 times their difference. Let x and у be the two parts ; then by the question we have „,. ж "т ^.~ ! Here z=24 — y, which...
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## A Treatise on the Elements of Algebra

Bewick Bridge - 1841 - 224 sider
...(x— yf=T2, or(*-y)2=4; .-. x— y=2.' Again, a? — 2xy+yf= 4, and 4xy = 96. a?+2xy+y2=100, Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. 18 and 6. Ex. 7. There are two numbers which are to each other...
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## Elements of Algebra

Charles Davies - 1842 - 358 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the...
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