 | Charles Davies - 1842 - 284 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | James Bates Thomson - 1844 - 266 sider
...have paid one guinea less for each. What was the number of oxen 1 Prob. 25. It is required to divide 24 into two such parts that their product shall be equal to 35 times their difference. Prob. 26. The sum of two numbers is 60, and their product is to the sum of their squares as 2 to 5.... | |
 | James Bates Thomson - 1844 - 272 sider
...those, whose difference, sum, and product, are as the numbers 2, 3 and 5, respectively 1 Prob. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between... | |
 | Charles Davies - 1845 - 382 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
 | Charles William Hackley - 1846 - 542 sider
...divide 100 inWtwo such parts that the sum of their square roots may be 14. II V Ana. 64 find 36. (19) It is required to divide the number 24 into two such parts that their product may be equal to 35 times their difference. f Ans. 10 and 14. (20) The sum of two tmmbers is 8, and... | |
 | Horatio Nelson Robinson - 1846 - 276 sider
...of yours, I can purchase the house. How much money had each of them! Ans. A had $160 . B $120 . 12. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided "by the less, may be to the quotient of the less part divided... | |
 | James Bates Thomson - 1846 - 276 sider
...those, whose difference, sum, and product, are as the numbers 2, 3 and 5, respectively 1 Prob. 12. Divide the number 24 into two such parts, that their product shall he to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference... | |
 | Jeremiah Day - 1847 - 358 sider
...whose difference, sum, and product, are as the numbers 2, 3, and 5, respectively 1 Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares, as 3 to 10. Ans. 18 and C. 13. In a mixture of rum and orandy, the difference... | |
 | 1847 - 386 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, ¿hat their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers... | |
 | John Bonnycastle - 1848 - 334 sider
...be subtracted from 10, and the remainder multiplied by the number itself, the product shall be 2 1 . Ans. 7 or 3. 3. It is required to divide the number...difference. Ans. 10 and 14. 4. It is required to divide the number 20 into two such parts, that twice the square of the greater part shall exceed three times... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
