| 1853 - 368 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. **It is required to divide the number 24 into two such parts, that** theirv product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers... | |
| Popular educator - 1854
...horse worth three times the 1st : what were the values of the two horses. Ans. £6, and £9. Prob. 25. **It is required to divide the number 24 into two such parts, that** the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| 1855
...are thoie, whose difference, sum and product, are as the numbers 2, 3 and 6, respectively ? Prob. 12. **Divide the number 24 into two such parts, that their product shall be** to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between... | |
| Charles Davies - 1856 - 205 sider
...whence, by the rule, x = 50 ± VT96"= 50 ± 14 ; hence, ж = 64, x — 36, and у = 36, у = 64. 11. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the... | |
| Charles Davies - 1859 - 299 sider
...13. Divide 100 into two such parts, that the sum of theii square roots may be 14. Ans. 64 and 36. 14. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14 15. The stun of two numbers is 8, and the... | |
| James B. Dodd - 1859 - 306 sider
...infinitely gfeat, to fulfil the conditions of the problem. - The problem is therefore impossible. EXAMPLE V. **To divide the number 24 into two such parts, that their product shall be** 150. If x represent one of the two parts, 24— z will represent the other and the equation will be... | |
| Charles Davies - 1860 - 400 sider
...10. Divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 11. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 12. What two numbers are they, whose product... | |
| Charles Davies - 1861 - 303 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
| Horatio Nelson Robinson - 1861
...| of yours, I can purchase the house. How much money had each of them? Ana. A had $160. B $120. 12. **It is required to divide the number 24 into two such parts,** mat the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Charles Davies - 1864 - 299 sider
...Divide 100 into two such parts, that the sum of their Hquare roots may be 14. Ans. 64 and 36. 14. It i» **required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
| |