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" It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. "
An Introduction to Algebra, with Notes and Observations: Designed for the ... - Side 136
av John Bonnycastle - 1829 - 312 sider
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Ray's Algebra, Part Second: An Analytical Treatise, Designed for High ..., Del 2

Joseph Ray - 1852 - 396 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. Ares. 7 or 3. 8. It is required to divide the number 24 into two such...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2...
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New Elementary Algebra: Containing the Rudiments of Science for Schools and ...

Horatio Nelson Robinson - 1866 - 312 sider
...two such parts, that the sum of the squares of those parts shall be b. Ans. £(a ± V26— a2). 4. It is required to divide, the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the...
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Elements of Algebra: For Colleges, Schools, and Private Students

Joseph Ray - 1866 - 406 sider
...10, and multiply the remainder by the number itself, the product shall be 21. Ans. Y or 3. 8. Divide 24 into two such parts that their product shall be...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2...
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New Elementary Algebra

Horatio Nelson Robinson - 1874 - 312 sider
...two such parts, that the sum of the squares of those parts shall be b. Am. £(a± v^¿) — a2). 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the...
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Key to Davies' Bourdon: With Many Additional Examples, Illustrating the ...

Charles Davies - 1879 - 277 sider
...2304. whence, by the rule, ж = 50±уТ96~=50 ± 14; hence, x = 64, x = 36, and у = 36, у = 64. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the...
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The Normal Elementary Algebra: Containing the First Priniples of the Science ...

Edward Brooks - 1888 - 336 sider
...The difference of two numbers is 6, and their product is 8-1; required the numbers. An». 12; 7. 6. Divide the number 24 into two such parts that their product shall be 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what...
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The Normal Elementary Algebra, Del 1

Edward Brooks - 1901
...6. The difference of two numbers is 5, and their product is 84 ; required the numbers. Am. 12; 7. 6. Divide the number 24 into two such parts that their product shall be 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what...
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Algebra Adapted to the Requirements of the First Stage of the ..., Del 2

Edward Mann Langley, S. R. N. Bradly - 1903
...person £5 a piece more than A. Now, how many persons were relieved by A and В respectively ? (26) It is required to divide the number 24 into two such parts that their product may be equal to 35 times their difference. (27) A and В set off at the same time to a place distant...
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New Elementary Algebra Embracing the First Principles of the Science

Charles Davies - 1891 - 294 sider
...13. Divide 100 into two such parts that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the...
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Ray's Algebra, Part First: On the Analytic and Inductive Methods of ...

Joseph Ray - 1848 - 240 sider
...of the symbol generally give both values of the unknown quantity, as in the following question. 4. Divide the number 24 into two such parts, that their product shall be 95. Let x= one of the parts ; then 24 — z= the other. And x(24— z)=95 Or x2— 24z=— 95 Whence...
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