| Joseph Ray - 1852 - 396 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. Ares. 7 or 3. 8. **It is required to divide the number 24 into two such...equal to 35 times their difference. Ans. 10 and 14.** 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
| Horatio Nelson Robinson - 1866 - 312 sider
...two such parts, that the sum of the squares of those parts shall be b. Ans. £(a ± V26— a2). 4. **It is required to divide, the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
| Joseph Ray - 1866 - 406 sider
...10, and multiply the remainder by the number itself, the product shall be 21. Ans. Y or 3. 8. Divide **24 into two such parts that their product shall be...equal to 35 times their difference. Ans. 10 and 14.** 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
| Horatio Nelson Robinson - 1874 - 312 sider
...two such parts, that the sum of the squares of those parts shall be b. Am. £(a± v^¿) — a2). 4. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
| Charles Davies - 1879 - 277 sider
...2304. whence, by the rule, ж = 50±уТ96~=50 ± 14; hence, x = 64, x = 36, and у = 36, у = 64. 11. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the... | |
| Edward Brooks - 1888 - 336 sider
...The difference of two numbers is 6, and their product is 8-1; required the numbers. An». 12; 7. 6. **Divide the number 24 into two such parts that their product shall be** 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what... | |
| Edward Brooks - 1901
...6. The difference of two numbers is 5, and their product is 84 ; required the numbers. Am. 12; 7. 6. **Divide the number 24 into two such parts that their product shall be** 140. Ans. 14; 10. 7. The difference of two numbers is 4 and the sum of their •quares is 208 ; what... | |
| Edward Mann Langley, S. R. N. Bradly - 1903
...person £5 a piece more than A. Now, how many persons were relieved by A and В respectively ? (26) **It is required to divide the number 24 into two such parts that their product** may be equal to 35 times their difference. (27) A and В set off at the same time to a place distant... | |
| Charles Davies - 1891 - 294 sider
...13. Divide 100 into two such parts that the sum of their square roots may be 14. Ans. 64 and 36. 14. **It is required to divide the number 24 into two such parts that their product** may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
| Joseph Ray - 1848 - 240 sider
...of the symbol generally give both values of the unknown quantity, as in the following question. 4. **Divide the number 24 into two such parts, that their product shall be** 95. Let x= one of the parts ; then 24 — z= the other. And x(24— z)=95 Or x2— 24z=— 95 Whence... | |
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