| George Lees - 1826
...— — = - — 4, the numerator. The •* Jc 2 4 fraction sought is therefore -. EXERCISES. Ex. 1. **It is required to divide the number 24 into two such parts, that** twice the greater may exceed three times the less by 3. Ans. 15 and 9. Ex. 2. What number is that,... | |
| Jeremiah Day - 1827 - 332 sider
...whose difference, sum, and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. **Divide the number 24 into two such parts, that their product shall be** to the sum of their squares, as 3 to 10. Ans. 18 and 6. 13. In a mixture of rum and brandy, the difference... | |
| Henry Ottley - 1828
...x2— 60z +900=36. (Extract the root,) and x— 30 =6, or x=36. Ans. the numbers are 24 and 36. 3. **Divide the number 24 into two such parts, that their product shall be** 35 times their difference. Let x=one part, then 24— x= the other, and 24 — 2x=the difference. Then... | |
| Bourdon (M., Louis Pierre Marie) - 1831 - 389 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2Q. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 21. The sum of two numbers is 8, and the... | |
| Charles Davies - 1835 - 353 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
| 1838 - 358 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
| Charles Davies - 1839 - 252 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their dif1 ference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
| John D. Williams - 1840 - 605 sider
...then by the question (10— x)x=2l, or я?— 10z= — 21. Whence ж=5±(25— 21)= б±2=7 or 3. 13. **It is required to divide the number 24 into two such...product shall be equal to 35 times their difference.** Let x and у be the two parts ; then by the question we have „,. ж "т ^.~ ! Here z=24 — y, which... | |
| Bewick Bridge - 1841 - 224 sider
...(x— yf=T2, or(*-y)2=4; .-. x— y=2.' Again, a? — 2xy+yf= 4, and 4xy = 96. a?+2xy+y2=100, Ex. 6. **To divide the number 24 into two such parts, that their product shall be** to the sum of their squares : : 3 : 10. 18 and 6. Ex. 7. There are two numbers which are to each other... | |
| Charles Davies - 1842 - 358 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. **It is required to divide the number 24 into two such parts, that their product** may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
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