 | Oxford univ, local exams - 1885
...with the square on the aforesaid part. 6. If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 7. To a... | |
 | GEORGE BRUCE HALSTED - 1885
...BD put a, and for DC put b, we get the theorem : If a sect is divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equivalent to the square on half the sect. 297.... | |
 | United States. Congress. Senate - 1880
...the line (.'/•' pa>-« through A. '¿. If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. Prove that... | |
 | George Bruce Halsted - 1886 - 366 sider
...BD put a, and for DC put b, we get the theorem : If a sect is divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equivalent to the square on half the sect. 297.... | |
 | Dalhousie University - 1887
...also themselves equal and parallel. 9. If a straight line !>e divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 10. Divide... | |
 | Canada. Department of the Interior - 1888
...are parallel to each other. 3. Show that if a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 4. Show... | |
 | Royal Military College, Sandhurst - 1890 - 132 sider
...method of proof must be geometrical^ 1. If a straight line be divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 2. In obtuse-angled... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 515 sider
...equivalent to sqs. on AC, CB. PROPOSITION 5. If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. ' Let AB... | |
 | Queensland. Department of Public Instruction - 1890
...these two sides is a right angle. 7. If a straight line be divided into two equal parts, and 11 also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 8. In obtuse-angled... | |
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If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line. 
