| Elias Loomis - 1858 - 256 sider
...that is, together with four right angles (Prop. V., Cor. 2). Therefore the angles of the polygon are equal to twice as many right angles as the figure has sides, wanting four right angles. Cor. 1. The sum of the angles of a quadrilateral is four right angles ; of a pentagon,... | |
| W. Davis Haskoll - 1858 - 422 sider
...and in an irregular polygon they may be all unequal. The interior angles of a polygon are together equal to twice as many right angles as the figure has sides, less four. On this is based the theory of the traverse, of which further explanation will be given... | |
| Charles Hutton - 1860 - 1020 sider
...measure the distance FA. To prove the work : add all the inward angles A, B, C, ice., together; fi» when the work is right, their sum will be equal to twice as many right u:ta as the figure has sides, wanting four right angles. But when there is an u>?l*. as F, that bends... | |
| Euclides - 1860 - 142 sider
...a polygon be produced to meet, the sum of the salient angles thus formed, with eight right angles, will be equal to twice as many right angles as the figure has sides. Let ABCDE be a polygon, and let its sides produced meet in F, G, H, T, K ; then the sum of the salient... | |
| Horatio Nelson Robinson - 1860 - 470 sider
...triangles is equal to two right angles, (Th. 11) ; and the sum of the angles of all the triangles must be equal to twice as many right angles as the figure has sides. But the sum of these angles contains the sum of four right angles about the point p ; taking these... | |
| Euclides - 1860 - 288 sider
...of a polygon be produced to meet, the sum of the salient angles thus formed with eight right angles, will be equal to twice as many right angles as the figure lias sides. 16. If on two opposite sides of a rectangle semicircles be described lying on corresponding... | |
| Royal college of surgeons of England - 1860 - 332 sider
...two right angles ; and all the angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 6. The opposite sides and angles of parallelograms are equal to one another, and the diameter bisects... | |
| Robert Potts - 1860 - 380 sider
...there are as many triangles as the figure has sides, therefore all the angles of these triangles are equal to twice as many right angles as the figure has sides ; but the same angles of these triangles are equal to the interior angtef of the figure together with... | |
| University of Madras - 1879 - 674 sider
...I. Prove that all the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. II. Prove the proposition to which the following is a corollary : The difference of the squares on... | |
| Rolla Rouse - 1879 - 400 sider
...40 ... ... ... ... ... 103 The exterior and interior angles of an rectilineal figure, are together equal to twice as many right angles as the figure has sides, 41 ... 104 „ angles are together equal to four right angles, 42 ... ... ... ... „ The interior... | |
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