 | Joseph Bateman - 1882 - 576 sider
...convenient number of feet and inches. For a Trapezoid (two of the sides parallel, but not equal).—Multiply half the sum of the two parallel sides by the perpendicular distance between them. For a Trape.zinm (four straight sides of different lengths).—Obtain a diagonal, by measuring from... | |
 | William John Macquorn Rankine - 1883 - 454 sider
...by a pair of' parallel straight lines, and a pair of straight lines not parallel). Multiply the half sum of the two parallel sides by the perpendicular distance between them. 3. Triangle. RULE A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
 | William Waterston - 1884 - 314 sider
...the square of 3 being 9, we have 9 X 3.1416 - 28-2744 square miles. 10. Area of a trapezoid: Multiply the sum of the two parallel sides by the perpendicular distance between them, and take half the product. Ex. The parallel sides are 4.32 feet and 5.48 feet, and the perpendicular 2.18... | |
 | 1885 - 630 sider
...Mensuration. Answer one Question. I. State and prove the rule for finding the area of a trapezoid. Multiply half the sum of the two parallel sides by...perpendicular distance between them, and the product will give the area. sides. The area of ABCDs=$ AB and CD x perpendicular distance BG between them. H Bisect... | |
 | Frank Eugene Kidder - 1886 - 640 sider
...(ce + i 2 FJ. '9-27 = area (Fig. 27). To Jind the area of a trrtpezoicl (Fig. 28). HULK. — Multiply the sum of the two parallel sides by the perpendicular distance between them, anil divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
 | John H. Macke - 1891 - 244 sider
...greater than a right angle, what is the proper definition of the angle? To find the area of a trapezoid. RULE. Multiply HALF THE SUM of the two parallel sides by the altitude of the trapezoid; that is, by the distance between the two parallel sides. Example. Find the... | |
 | Frank Eugene Kidder - 1892 - 1032 sider
...X (ce + di) F'3.27 = area (Fig. 27). To find, the area of a trapczoid (Fig. 28). RULE. — Multiply the sum of the two parallel sides by the perpendicular distance between them, and divide the product by 2. To compute the area of an irregular polygon. RULE. — Divide the polygon... | |
 | 1894 - 330 sider
...as in previous problem. Fig. 49. PROB. V 1 1 . — To find the area of a trapezoid. Multiply half of the sum of the two parallel sides by the perpendicular distance between them, and p .c the product will be the / \ area. / \ \ Example. — Let ABCD (Fig. 49) be a trapezoid. The side... | |
 | Thomas Aloysius O'Donahue - 1896 - 186 sider
...multiply the base by half the perpendicular. PROB. VII. To find the area of a trapezoid. Multiply half of the sum of the two parallel sides by the perpendicular...distance between them, and the product will be the area. Let ABCD (Fig. 61) be a trapezoid. The side EC = 40, Fio. 61. Pra. 62. AD = 25, and DE = 18 ; required... | |
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RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 
