| Oxford univ, local exams - 1885
...and the four definitions concerning segments of circles. 2. If two triangles have two angles of the **one equal to two angles of the other, each to each, and** one side equal to one side; viz. the sides adjacent to the equal angles in each; then shall the other... | |
| Webster Wells - 1886 - 371 sider
...angle may be found by subtracting this sum from two right angles. 73. COROLLARY III. If two triangles **have two angles of one equal to two angles of the other,** the third angles are also equal. 75. COROLLARY V. The sum of the acute angles of a right triangle is... | |
| E. J. Brooksmith - 1889
...geometrical. Great importance will be attached to accuracy.] 1. If two triangles have two angles of the **one equal to two angles of the other, each to each, and** one side equal to one side, viz., sides which are opposite to equal angles in each ; then shall the... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 515 sider
...Proposition is it an immediate inference ? PROPOSITION 26. THEOREM. If two triangles have two angles of the **one equal to two angles of the other, each to each, and** one side equal to one side, namely, either the sides adjacent to the equal angles or sides which are... | |
| Euclid - 1890 - 400 sider
...must be on D. Proposition 26. (Second Part.) THEOREM — If tivo triangles have two angles of tlie **one equal to two angles of the other, each to each, and** have likewise the sides equal which are opposite one pair of equal angles ; then the triangles are... | |
| Queensland. Department of Public Instruction - 1892
...line of unlimited length, from a given point without it. 5. If two triangles have two angles of the **one equal to two angles of the other, each to each, and the** side adjacent to the equal angles of the one equal to the side adjacent to the angles of the other... | |
| Euclid, John Bascombe Lock - 1892 - 167 sider
...respectively ; prove that DA=EB=FC. Proposition 26. PART I. 54. If two triangles have two angles of the **one equal to two angles of the other, each to each, and** also the sides adjacent to the equal angles equal, the two triangles are equal in all respects. Let... | |
| Henry Sinclair Hall, Frederick Haller Stevens - 1892 - 147 sider
...4. For ^ADB = ^AFD [in. 32]. And since AD = AF (radii), .'. L ADF = AFD. Hence the two A8 ABD, ADF **have two angles of one equal to two angles of the other,** and the side AD common, .'. BD = OF. 5. For these two circles circumscribe A8 which have equal bases... | |
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