 | Oxford univ, local exams - 1885
...and the four definitions concerning segments of circles. 2. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side; viz. the sides adjacent to the equal angles in each; then shall the other... | |
 | Webster Wells - 1886 - 371 sider
...angle may be found by subtracting this sum from two right angles. 73. COROLLARY III. If two triangles have two angles of one equal to two angles of the other, the third angles are also equal. 75. COROLLARY V. The sum of the acute angles of a right triangle is... | |
 | E. J. Brooksmith - 1889
...geometrical. Great importance will be attached to accuracy.] 1. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz., sides which are opposite to equal angles in each ; then shall the... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 515 sider
...Proposition is it an immediate inference ? PROPOSITION 26. THEOREM. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, namely, either the sides adjacent to the equal angles or sides which are... | |
 | Euclid - 1890 - 400 sider
...must be on D. Proposition 26. (Second Part.) THEOREM — If tivo triangles have two angles of tlie one equal to two angles of the other, each to each, and have likewise the sides equal which are opposite one pair of equal angles ; then the triangles are... | |
 | Queensland. Department of Public Instruction - 1892
...line of unlimited length, from a given point without it. 5. If two triangles have two angles of the one equal to two angles of the other, each to each, and the side adjacent to the equal angles of the one equal to the side adjacent to the angles of the other... | |
 | Euclid, John Bascombe Lock - 1892 - 167 sider
...respectively ; prove that DA=EB=FC. Proposition 26. PART I. 54. If two triangles have two angles of the one equal to two angles of the other, each to each, and also the sides adjacent to the equal angles equal, the two triangles are equal in all respects. Let... | |
 | Henry Sinclair Hall, Frederick Haller Stevens - 1892 - 147 sider
...4. For ^ADB = ^AFD [in. 32]. And since AD = AF (radii), .'. L ADF = AFD. Hence the two A8 ABD, ADF have two angles of one equal to two angles of the other, and the side AD common, .'. BD = OF. 5. For these two circles circumscribe A8 which have equal bases... | |
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