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" FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of... "
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Side 183
av Euclid - 1765 - 464 sider
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The Elements of Euclid, the parts read in the University of Cambridge [book ...

Euclides - 1846
...each to each, and therefore FH is equal to FK : And in like manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another, and the circle described from the centre...
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The geometry, by T. S. Davies. Conic sections, by Stephen Fenwick

Royal Military Academy, Woolwich - 1853
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the...
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The first six books of the Elements of Euclid, with numerous exercises

Euclides - 1853 - 147 sider
...perpendicular fh is equal to the perpendicular f k. In the same manner, it may be demonstrated that ft fm, fg are each of them equal to fh, or fk : therefore the five straight lines fg, fh, f fc f 1, fm are equal to one another : wherefore the circle described from...
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The synoptical Euclid; being the first four books of Euclid's Elements of ...

Euclides - 1853
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that 8. FL, FM, FG, are each of them equal to FH or FK: therefore 9. The five straight lines FG, FH, FK, FL, FM, are equal to one another; wherefore the circle described...
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The Elements of geometry; or, The first six books, with the eleventh and ...

Euclides - 1855
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may be shown that FL, FM, and FG, are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1860 - 361 sider
...perpendicular FH is equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the...
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Euclid's Elements of plane geometry [book 1-6] explicitly enunciated, by J ...

Euclides - 1860
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, and FG are each of them equal to FH or FK ; therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another ; wherefore the circle described from...
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The school Euclid: comprising the first four books, by A.K. Isbister

Euclides - 1862
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, FM, FG, are each of them equal to FH or FK ; therefore the five straight linos FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the...
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The elements of plane geometry; or, The first six books of Euclid, ed. by W ...

Euclides - 1863
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may shown that FL, FM, and FG are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre...
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The school edition. Euclid's Elements of geometry, the first six books, by R ...

Euclides - 1864
...perpendicular FHis equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the...
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