 FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...  Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Side 183av Euclid - 1765 - 464 siderUten tilgangsbegrensning - Om denne boken
 | Euclid, John Playfair - 1846 - 334 sider
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
 | Royal Military Academy, Woolwich - 1853 - 400 sider
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
 | Euclides - 1853 - 176 sider
...perpendicular fh is equal to the perpendicular f k. In the same manner, it may be demonstrated that ft fm, fg are each of them equal to fh, or fk : therefore the five straight lines fg, fh, f fc f 1, fm are equal to one another : wherefore the circle described from... | |
 | Euclides - 1853 - 146 sider
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that 8. FL, FM, FG, are each of them equal to FH or FK: therefore 9. The five straight lines FG, FH, FK, FL, FM, are equal to one another; wherefore the circle described... | |
 | Euclides - 1855 - 270 sider
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may be shown that FL, FM, and FG, are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
 | Robert Potts - 1860 - 380 sider
...perpendicular FH is equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
 | Euclides - 1860 - 288 sider
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, and FG are each of them equal to FH or FK ; therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another ; wherefore the circle described from... | |
 | Euclides - 1862 - 172 sider
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, FM, FG, are each of them equal to FH or FK ; therefore the five straight linos FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... | |
 | Euclides - 1863 - 122 sider
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may shown that FL, FM, and FG are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
 | Euclides - 1864 - 448 sider
...perpendicular FHis equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
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