 | Whitman Peck - 1868 - 304 sider
...its lowest terms, or cancel any factor common to the first lerm and either the second or third. Then multiply the second and third terms together, and divide by the first. Compound Numbers must be reduced to the lowest denomination mentioned, and the first and second terms... | |
 | rev. Frederick Calder - 1869 - 258 sider
...„ . . nomination, therefore no . L- I ~ I ' »'. '5''. 1 i - • ( T reduction is required. I now multiply the second and third terms together, and divide by the first : the answer is £12 13s. 4rL And this fourth term and the other three terms form the following proportion... | |
 | Ezra S. Winslow - 1872 - 256 sider
...to which it relates. there are any factors pertaining to the fourth term, affix, them to the first; multiply the second and third terms together and divide by the first, and the quotient is the answer, term, or portion of a term. sought. EXAMPLE. —If 12 horses in 6 days... | |
 | H T. Sortwell - 1873 - 176 sider
...days than in 7 days, we write 48 in the second term, and 7 in the first term. We have then merely to multiply the second and third terms together, and divide by the first. This operation may sometimes be considerably curtailed by the process called cancelling, which was... | |
 | 1874 - 668 sider
...The abstract method runs thus : As five yards is to seven yards, so is three dollars to the answer. Multiply the second and third terms together, and divide by the first term; which gives the answer, four dollars and twenty cents. These two processes need only to be thus... | |
 | 1874 - 524 sider
...The abstract method runs thus : As five yards is to seven yards, so is three dollars to the answer. Multiply the second and third terms together, and divide by the first term; which gives the answer, four dollars and twenty cents. These two processes need only to be thus... | |
 | W. P. Higgs - 1876 - 120 sider
...of x, it is only necessary to divide the product of b bc and c by a ; or x = — In other words, we multiply the ££ second and third terms together, and divide by the first, to find the fourth term, or the answer. In arithmetic, too, we are told that " the mean proportional... | |
 | James Cornwell - 1878 - 386 sider
...other. How is a Rule of Three sum to be stated ? Why ? How is it to be solved after stating Why ? When I multiply the second and third terms together and divide by the first, what truth is taken for granted ? When and how are ratios compounded ? Give examples. What operation... | |
 | Montagu H. Foster - 1881 - 182 sider
...less, the quantity purchased or sold will be less, or, if greater, greater. For the Operation. — Multiply the second and third terms together, and divide by the first : the quotient will be the quantity required, in the same name as the third term : it may be reduced to a higher name... | |
 | Frederick J. Edwards - 1882 - 108 sider
...PROPORTION. CASE XCVII. To find the Fourth Term of a Proportion when Three Terms are given. RULE : Multiply the second and third terms together, and divide by the first. NB — This rule is much simplified by dividing first, or by striking out the common factors of the... | |
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Sir," said I, after puzzling a long time over "more requiring more and less requiring less" — "will you tell me why I sometimes multiply the second and third terms together and divide by the first — and at other times multiply the first and second... 
