 | Charles Astor Bristed - 1852 - 470 sider
...every triangle are equal to two right angles. 3. Divide a given straight line into two such parts, that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. 4. The angle at the centre of a circle is double of the angle at the circumference,... | |
 | 1852 - 478 sider
...general one ? 2. To divide a given straight line into two parts, so that the rectangle contained hy the whole and one of the parts, shall be equal to the square of the other part. Can this be solved arithmetically ? if so, find approximately into how many parts... | |
 | Royal Military Academy, Woolwich - 1853 - 400 sider
...AC, CD. Wherefore, if a straight line, etc. QED PROPOSITION XI. PROB. To divide a given straight line into two parts, so that the rectangle contained by...and one of the parts, shall be equal to the square of the other part. Upon AB describe (46. i.) the square ABDC ; bisect (10. i.) AC in E, and join BE... | |
 | Euclides - 1853 - 176 sider
...Wherefore, if a straight line, &c. QED PROPOSITION XI. — PROBLEM. To divide a given straigM line into two parts, so that the rectangle contained by...and one of the parts shall be equal to the square of the other part. LET ab be the given straight line ; it is required to divide it into two parts,... | |
 | Euclides - 1853 - 146 sider
...equal to the square of the other part. Let AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by...and one of the parts, shall be equal to the square of the other part. Upon AB describe (1. 46.) the square ABDC ; bisect (I. 10.) AC in E, and join BE;... | |
 | William Somerville Orr - 1854 - 534 sider
...sec the remarks at the end of this book. PROPOSITION XI.— PROBLEM. To divide a given straight line (AB) into two parts, so that the rectangle contained by the whole, and от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and... | |
 | Great Britain. Committee on Education - 1855 - 976 sider
...two sides of it, the angle contained by those two sides is a right angle. 3. Divide a straight line into two parts, so that the rectangle contained by...and one of the parts shall be equal to the square of the other part. Section 3. 1. The angles in the same segment of a circle are equal. 2. If from a... | |
 | Robert Potts - 1855 - 1050 sider
...two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line into two parts, so that the rectangle contained by...and one of the parts, shall be equal to the square of the other part Solve the same problem algebraically, and give the geometrical interpretation of... | |
 | Euclides - 1855 - 270 sider
...one of the parts, shall be equal to the square oflhe other part. Let AB be the given straight line. It is required to divide AB into two parts, so that the rectangle contained by the whole and one of tLe parts, shall be equal to the square of the other part. Upon AB describe (I. 46) the square СB.... | |
 | Cambridge univ, exam. papers - 1856 - 252 sider
...each of the parts, are together equal to the square of the whole line. 7. Divide a given straight line into two parts, so that the rectangle contained by...and one of the parts, shall be equal to the square of the other part. 8. If two circles cut one another, they shall not have the same centre. 9. If two... | |
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To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part. 
