 | University of Durham - 1851 - 222 sider
...twice the rectangle contained by the parts. 5. To divide a given straight line into two parts, such that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. 6. If two circles cut one another they cannot have the same... | |
 | Bengal council of educ - 1852 - 348 sider
...angle. Is this proposition included in any more general one ? (2.) To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part. Can this be solved arithmetically ? if so, find approximately... | |
 | Euclides - 1852 - 152 sider
...PROP. X. PEOB. To bisect a (jiven finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line; it is required to divide it into two equal parts. Describe " upon it an equilateral triangle ABC, and bisect b the angle ACB by the straight... | |
 | Charles Astor Bristed - 1852 - 470 sider
...every triangle are equal to two right angles. 3. Divide a given straight line into two such parts, that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. 4. The angle at the centre of a circle is double of the angle... | |
 | Euclides - 1853 - 334 sider
...two such parts, that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Let AB be the given...straight line. It is required to divide it into two such parts, that the rectangle contained by the whole line and one of the parts shall be equal to the... | |
 | Royal Military Academy, Woolwich - 1853 - 400 sider
...PROPOSITION X. PROB. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line; it is required to divide it into two equal parts. Describe (1. i.) upon it an equilateral triangle ABC, and bisect (9. i.) the angle ACB... | |
 | Euclides - 1853 - 176 sider
...X. — PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. LET ab be the given straight line, it is required to divide it into two equal parts. Describe (i. 1) upon ab an equilateral triangle abc, and bisect (i. 9) the angle acb by... | |
 | Euclides - 1853 - 146 sider
...PROP. X. PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line ; it is required to divide it into two equal parts. Describe (I. 1.) upon it an equilateral triangle ABC, and bisect (I. 9.) the angle ACB... | |
 | William Somerville Orr - 1854 - 534 sider
...the remarks at the end of this book. PROPOSITION XI.— PROBLEM. To divide a given straight line (AB) into two parts, so that the rectangle contained by the whole, and от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and... | |
 | John Playfair - 1855 - 334 sider
...rectangle contained by the whole, and one of the parts, may be equal to the square of the other part. I Let AB be the given straight line; it is required...contained by the whole, and one of the parts, shall be equal to the square of the other part. EF equal to EB, and upon AF describe A! _ |3T Upon AB describe... | |
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AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. 
