| Charles Davies - 1840 - 266 sider
...whose difference, multiplied by the lesser, is equal to 12 1 Ans. 4 and 7, or | y^a" and y -v/lT. 13. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 04 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be... | |
| John D. Williams - 1840 - 634 sider
...then by the question (10— x)x=2l, or я?— 10z= — 21. Whence ж=5±(25— 21)= б±2=7 or 3. 13. It is required to divide the number 24 into two such parts, that their product shall be equal to 35 times their difference. Let x and у be the two parts ; then by the question we... | |
| Bewick Bridge - 1841 - 260 sider
...(x— yf=T2, or(*-y)2=4; .-. x— y=2.' Again, a? — 2xy+yf= 4, and 4xy = 96. a?+2xy+y2=100, Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. 18 and 6. Ex. 7. There are two numbers which are to... | |
| Charles Davies - 1842 - 284 sider
...equal to 77 ; and whose difference, multiplied by the lesser, is equal to 12 ? Ans. 4 and 7, or 13. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36 14. It is required to divide the number 24 into two such parts, that their product may be equal to... | |
| Charles William Hackley - 1846 - 542 sider
...subtract it from 10, and multiply the remainder by the number itself, the product shall be 21. (18) To divide 100 into two such parts that the sum of their square roots may be 14. Aus. 64 and 3G. (19) It is required to divide the number 24 into two such parts that their product... | |
| Charles William Hackley - 1846 - 544 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 7, or 3. (18) To divide 100 into two such parts that the sum of their square rootsmay be 14. Ans. 64 and 36. (19) It is required to divide the number 24 into two such parts that... | |
| Elias Loomis - 1846 - 376 sider
...such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2. To divide the number a into two such parts, that the sum of their square roots may be b. Ans. -¿ + -= \/ 2a— 62 and — \/ 2a— 6a. 3. The sum of two numbers is 7, and the sum of their... | |
| Elias Loomis - 1846 - 380 sider
...such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2. To divide the number a into two such parts, that the sum of their square roots may be b. b .-- Ans. -g + -3 V2a— b2 and — — -\/2a — b3. 3. The sum of two numbers is 7, and the sum... | |
| Horatio Nelson Robinson - 1846 - 276 sider
...of yours, I can purchase the house. How much money had each of them! Ans. A had $160 . B $120 . 12. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided "by the less, may be to the quotient of the less part divided... | |
| Charles William Hackley - 1846 - 542 sider
...the remainder by the number itself, the product shall bo 21. Ans. 7, or 3. (18) To divide 100 inWtwo such parts that the sum of their square roots may be 14. II V Ana. 64 find 36. (19) It is required to divide the number 24 into two such parts that their product... | |
| |