| Benjamin Greenleaf - 1852 - 348 sider
...of equal width, whose area is 448 square inches. What is the width of the frame ? Ans. 4 inches. 39. Divide 100 into two such parts that the sum of their square roots may be 14. Ans. 64 and 36. 40. A square court-yard has a rectangular gravel walk around it. The side of the court wants one yard... | |
| Joseph Ray - 1852 - 408 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. " Ans. 7 or 3. 8. It is required to divide the number 24 into two such parts that their product shall be equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such... | |
| 1853 - 380 sider
...whose difference, multiplied by the lesser, is equal to 12 ? . Ans. 4 and 7, or f f2 and y ^/~2. 3. To divide 100 into two such parts, that the sum of...to divide the number 24 into two such parts, that theirv product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers... | |
| Benjamin Greenleaf - 1854 - 374 sider
...of equal width, whose area is 448 square inches. What is the width of the frame ? Ans. 4 inches. 39. Divide 100 into two such parts that the sum of their square roots shall be 14. Ans. 64 and 36. 40. A square court-yard has a rectangular gravel-walk around it. The side... | |
| Popular educator - 1854 - 940 sider
...horse worth three times the 1st : what were the values of the two horses. Ans. £6, and £9. Prob. 25. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
| Elias Loomis - 1855 - 356 sider
...two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2. Divide the number a into two such parts, that the sum of their square roots may be ft. 3. The sum of two numbers is 8, and the sum of their fourt> powers is 706. What are the numbers... | |
| George Roberts Perkins - 1856 - 276 sider
...B.'s money, which was $50 more than A.'s, was in trade 5 months. What was A.'s stock ? Ans. $100. 14. It is required to divide the number 24 into two such parts, that their product may bo equal to 35 times their difference. What are the parts? Ans. 10 and 14. 15. A company at a tavern... | |
| Charles Davies - 1856 - 224 sider
...lower sign, p — — = -ps > substituting in (4), /144 t y = \/ -5- — 4 ; whence, x = ~. V У 10. Divide 100 into two such parts, that the sum of their square roots may be 14. Let x and у denote the parts. From the conditions, x+ у = 100 ... (1), ^ + Vy= 14 ... (2): squaring... | |
| Elias Loomis - 1856 - 280 sider
...the two numbers thus obtained shall be 300 ? Ans. 12 and 10, or 16 and 7£. Ex. 30. Divide the number 100 into two such parts that the sum of their square roots may be 14. Ans. 36 and 64. Ex. 31. From two places at a distance of 720 miles, two persons, A and B, set out at the... | |
| Theodore Strong - 1859 - 570 sider
...often so represent whatever ia to be found, as immediately to obtain a pure quadratic. Thus, if we wish to divide 100 into two such parts, that the sum of their square roots may be 14 ; then if we represent the roots by 7 + x and 1-х, their sum will equal 14, and we shall get (7 +... | |
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