 | Euclides - 1816 - 588 sider
...equal circles, and the equal angles BGC, EHF at their centres, and BAC, EDF at their circumterences : The circumference BKC is equal to the circumference ELF. Join BC, EF ; and because the circles ABC, DEF, are equal, the straight lines drawn from their centres are equal : Therefore... | |
 | John Playfair - 1819 - 354 sider
...ABC, DEF are equal, the straight lines drawn from their centres are equal : therefore the two A sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4. 1.) to the base EF : and because the angle at A is equal to the angle at D, the... | |
 | Euclid, Robert Simson - 1821 - 514 sider
...ABC, DEF are equal, the straight lines drawn from their centres are equal; therefore the two sides BG, GC are equal to the two EH, HF; and the angle at G is equal to the angle at H;thereforethe base BC is equal (4. 1. Jto the base EF; and because the angle at A is equal to the... | |
 | Peter Nicholson - 1825 - 1046 sider
...circumferences. Let ABC, DEF be equal circles, and the equal angles BGC, EHF et their centres, and ВАС, EDF at their circumferences : The circumference BKC...equal to the circumference ELF. Join BC, EF ; and because the circles ABC, DEF, are equal, the »raight lin?s drawn from their centres are equal : Therefore... | |
 | George Lees - 1826 - 276 sider
...Then, because the circles are equal, their radii are equal ; therefore, the two sides BG, GC, are B equal to the two EH, HF ; and the angle at G is equal to the angle at Hs ; therefore, the base BC is equal to the base EFa. Conceive the circle ABC applied to the circle... | |
 | Euclid, John Playfair - 1826 - 326 sider
...straight lines drawn from their eentres are equal: theref«re tJie tw« A / 43^ nr mf ""•' (a iides BG, GC, are equal to the two EH, HF; and the angle at G is equ .Ito the angle at H; therefore the base BC is equal (4. i.) to the base EF : and beeavse the angle... | |
 | Euclid - 1826 - 234 sider
...^S\\ ) ( / /\\ ) • Def. I. lines drawn from their centres shall also be equal : therefore the two BG, GC, are equal to the two EH, HF, and the angle at G equal to the angle at н. Wherefore also the base Bcb is equal to the base EF. Again, because the angle... | |
 | Euclides - 1826 - 226 sider
....Д\ ) ( / _Д\ } • Def. I. lines drawn from their centres shall also be equal: therefore the two BG, GC, are equal to the two EH, HF, and the angle at G equal to the angle at н. Wherefore also the base at A is equal to the angle at D, the segment BAC... | |
 | Euclid, Robert Simson - 1829 - 548 sider
...drawn from their centres are equal : therefore the two sides BG, GC are equal to the two EH, HF ; and K the angle at G is equal to 'the angle at H ; therefore the base BC is equal (4. 1. ) to the base EF; and because the angle at A is equal to the angle atD, the... | |
 | John Playfair - 1832 - 358 sider
...are equal, the .straight lines drawn from their centres are equal : therefore the two AD CE sides EG, GC, are equal to the two EH, HF; and the angle at G is equal to the angle at H; therefore the base BC is equal (4. 1.) to the base EF: and because the angle at A is equal to the angle at D, the... | |
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ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is... 
