| Benjamin Greenleaf - 1850 - 368 sider
...them one by one to the basket ? Ans. 288090 miles 2 rods. PROBLEM III. Ans. 399 years. The extremes and the common difference being given, to find the number of terms. Illustration. — Let the extremes be 3 and 19, and the common difference 2. The difference of the... | |
| John Bonnycastle - 1851 - 314 sider
...by which his journey is daily augmented. Ans. Daily increase, 5 miles. PROBLEM II. The two extremes, and the common difference being given, to find the...number of terms. RULE. Divide the difference of the extremes by the common difference, and the quotient, increased by 1, will be the number of terms required.*... | |
| Charles Haynes Haswell - 1851 - 346 sider
...of a clock strike in 12 hours 1 12X(13~-2)~78 J3ns. When the Common Difference and the Extremes are given, to find the Number of Terms. RULE.— Divide the difference of the extremes by the common difference, and add one to the quotienL EXAMPLE. — A man travelled 3 miles... | |
| Charles Haynes Haswell - 1853 - 318 sider
...a clock strike in 12 hours ? 12X (13-7-2) = 78 Mns. When the Common Difference and the Extremes are given, to find the Number of Terms. RULE. — Divide the difference of the extremes by the common difference, and add one to the quotient. EXAMPLE. — A man travelled 3 miles... | |
| Ezra S. Winslow - 1853 - 264 sider
...- 2 - = greater extreme. 2s-rn — e = greater extreme. The extremes of an arithmetical progression and the common difference being given, to find the number of terms. E — eS- d -\-l= number of terms. EXAMPLE. — As a heavy body, falling freely through space, descends... | |
| James Stewart Eaton - 1857 - 376 sider
...the number of additions; ie the number of terms less one. Hence, 34:8. PROB. 3. — The extremes and common difference being given to find the number of terms, RULE. — Divide the difference of the extremes by the common difference, add 1 to the quotient and the sum will be the number of terms. Ex.... | |
| Charles Guilford Burnham - 1857 - 342 sider
...purchased. Therefore — Arti 239«— When the first and last terms, and the common difference are given, to find the number of terms — RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If... | |
| Charles Guilford Burnham - 1857 - 328 sider
...purchased. Therefore — Art, 289. — When the first and last terms, and the common difference* are given, to find the number of terms — RULE. Divide the difference of the extremes by the common difference, and the quotient will be 1 less than the number of terms. 10. If... | |
| David Price - 1858 - 264 sider
...last day ; at what rate did he increase his speed ? Ans. 2 mi. per day. IV. The two extremes, and tJie common difference being given, to find the number of terms. RULE. — Divide the difference between the two extremes by the common difference, and to the quotient add 1 for the required number... | |
| Emerson Elbridge White - 1861 - 348 sider
...the extremes by the number of terms, less one. (3). The first term, common difference, and last term being given to find the number of terms. RULE. — Divide the difference of the extremes by the common difference, and add 1 to the quotient. (4). The first term, number of terms,... | |
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