 | Royal Military Academy, Woolwich - 1853 - 400 sider
...Wherefore, if a straight line, etc. QED PROPOSITION XI. PROB. To divide a given straight line into two parts, so that the rectangle contained by the whole,...parts, shall be equal to the square of the other part. Upon AB describe (46. i.) the square ABDC ; bisect (10. i.) AC in E, and join BE ; produce CA to F,... | |
 | Royal Military Academy, Woolwich - 1853 - 476 sider
...divide a line of 20 inches in length into two parts such that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Let x = the greater part ; then 20 — x = the less part, and hence by the question we have x8 = 20 (20... | |
 | Euclides - 1853 - 334 sider
...line. It is required to divide it into two such parts, that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. On AB describe (i. 46) the square ACDB ; and supposing A to be that extremity of AB adjacent to which... | |
 | William Walton, Charles Frederick Mackenzie - 1854 - 266 sider
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
 | Cambridge univ, exam. papers - 1854 - 284 sider
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
 | William Somerville Orr - 1854 - 534 sider
...divide a given straight line (AB) into two parts, so that the rectangle contained by the whole, and от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and equal to AB;* bisect AC in E,t and draw BE. Prolong С A to F, making... | |
 | Robert Potts - 1855 - 1050 sider
...parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line into two parts, so that the rectangle contained by the whole,...parts, shall be equal to the square of the other part Solve the same problem algebraically, and give the geometrical interpretation of the result. 4. The... | |
 | Great Britain. Committee on Education - 1855 - 976 sider
...of it, the angle contained by those two sides is a right angle. 3. Divide a straight line into two parts, so that the rectangle contained by the whole...parts shall be equal to the square of the other part. Section 3. 1. The angles in the same segment of a circle are equal. 2. If from a point without a circle... | |
 | Euclides - 1855 - 270 sider
...the square oflhe other part. Let AB be the given straight line. It is required to divide AB into two parts, so that the rectangle contained by the whole and one of tLe parts, shall be equal to the square of the other part. Upon AB describe (I. 46) the square СB.... | |
 | Cambridge univ, exam. papers - 1856 - 200 sider
...parts are together equal to the square of the whole line. 7. To divide a given straight line into two parts, so that the rectangle contained by the whole...parts shall be equal to the square of the other part. 8. If a straight line drawn through the centre of a circle bisect a straight line in it, which does... | |
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To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part. 
