 | Stephen Pike - 1824 - 212 sider
...less 1, by the common difference, and to the product add the first term, the sum is the last term. 2. Multiply the sum of the two extremes by the number...product will be the sum of all the terms. EXAMPLES. 1. The first term of a certain series in arithmetical progression is 2, the common difference is 2, and... | |
 | Zachariah Jess - 1824 - 224 sider
...less 1, by the common difterence, and to that product add the first term, the sum is the last term. Secondly, Multiply the sum of the two extremes by...of terms, and half the product will be the sum of the series. EXAMPLES. EXAMPLES. 1 Bought 19 yards of shalloon, at Id. for the first yard, 3d. for the... | |
 | Thomas Tucker Smiley - 1825 - 224 sider
...first term' the sum is the last term. 2. Add the first and last terms together, and multiply the sum by the number of terms, and half the product will be the sum of all the terms. Case 2. When the first and last terms (or two extremes,) are given to find the common difference. Rule... | |
 | Silvestre François Lacroix - 1825 - 394 sider
...progression ; and may be reduced to the following rule : Multiply the sum of the first and the last term by the number of terms, and half the product will be the sum of the wJutle progression. Or, which amounts to the same, multiply the sum of tlie first and the last... | |
 | Zadock Thompson - 1826 - 176 sider
...and the number of terms given, to find the sum of all the terms. RULE.* — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. Examples. 1. The first term of an arithmetical progression is 1, the last term 21, and the... | |
 | Zachariah Jess - 1827 - 226 sider
...add the first term, the sum is the last term. Secondly, Multiply the sum of the first and last term by the number of terms, and half the product will be the sum of the series. EXAMPLES. 1. Bought 19 yards of shalloon, at 1 cent for the first yard, 3 cents for the... | |
 | Montgomery Robert Bartlett - 1828 - 426 sider
...term, the sum will be the last term. 2. Add the first and the last terms together, and multiply the sum by the number of terms, and half the product will be the sum of all the terms. Thus:— • (1) What is the last term, and the number of terms of an arithmetical progression whose... | |
 | Daniel Parker - 1828 - 358 sider
...and the number of terms being given, to find the stun of all the terms. RULE. Multiply the sum of the extremes by the number of terms, and half the product will be the sum of the terms. Examples. 53+5=68 The sum of the extremes. Then 58x9+2=261 Ans, а. How many strokes does... | |
 | James L. Connolly (mathematician.) - 1829 - 266 sider
...The first term, the last term, and the number of terms, given to find the sum of all the terms. RULB. Multiply the sum of the two extremes by the number of terms, and half that product will be the answer; or multiply the sum of the two extremes by half the number of terms;... | |
 | William Kinne - 1829 - 246 sider
...the number of terms being given, to find the sum of all the terms. HOLE. — Multiply the sum of the extremes by the number of terms, and half the product will be the answer. EXAMPLES. 1. The first term of an arithmetical progression is 1, the last term 21, the number... | |
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The first term, common difference, and number of terms given, to find the .last term, and sum of all the terms. 
