| Euclid, Isaac Todhunter - 1883 - 428 sider
...is bisected by the straight line AF. QEF PROPOSITION 10. PROBLEM. To bisect a given finite straight line, that is to divide it into two equal parts. Let AB be the given straight line : it is required to divide it into two equal parts. Describe on it an equilateral triangle... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 538 sider
...figure, and AF is called its axis of symmetry. PROPOSITION 10. PROBLEM. To bisect a given finite straight line — that is, to divide it into two equal parts. Let AB be the given straight line; it is required to divide it into two equal parts. Describe on AB an equilateral A ABC.... | |
| Thomas Aloysius O'Donahue - 1896 - 186 sider
...third can be found. Let BA = 16 and AC = 1 2 to find BC. HI Problems I. To bisect a given straight line, that is, to divide it into two equal parts. Let AB (Fig. 48) be the given line. From the centres A and AE Fio. 49. B and with any radius — greater than... | |
| Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 330 sider
...3. Divide an angle into four equal parts. PROPOSITION 10. PROBLEM. To Useel a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line. It is required to divide AB into two equal parts. Constr. On AB describe an equilateral... | |
| Euclid, Rupert Deakin - 1903 - 218 sider
...is bisected by the straight line AF. QEF PROP. 19.— Problem.— To bisect a given finite straight line; that is, to divide it Into two equal parts. Let AB be the given finite straight line. It is required to divide AB into two equal parts. Construction. — On AB describe... | |
| Euclid - 1904 - 488 sider
...shew that AF also bisects the angle DFE. PROPOSITION 10. PROBLEM. To Usect a given finite straight line, that is, to divide it into two equal parts Let AB be the given straight line. It is required to divide AB into two equal parts. Constr. On AB describe an equilateral... | |
| Thomas Aloysius O'Donahue - 1911 - 288 sider
...two sides, the magnitude of the third can be : 12 to find BC. Problems I. To bisect a given straight line, that is, to divide it into two equal parts. Let AB (Fig. 48) be the given line. From the centres A and AE FIG. 49. B B and with any radius—greater than... | |
| |