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" Subtract the cube thus found from the said period, and to the remainder bring down the next period, and call this the dividend. "
The Scholar's Arithmetic: Designed for the Use of Schools in the United States - Side 173
av Jacob Willetts - 1822 - 191 sider
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The Progressive Practical Arithmetic: Containing the Theory of Numbers, in ...

Horatio Nelson Robinson - 1859 - 362 sider
...and write its root for the first figure in the required root; subtract the cube from the left hand period, and to the remainder bring down the next period for a/ dividend. III. At the, left of the dividend write three times the square of the first fyurc of the...
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The Progressive Higher Arithmetic, for Schools, Academies, and Mercantile ...

Horatio Nelson Robinson - 1860 - 444 sider
...and write its root for the first figure in the required root; subtract, the cube from the left hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write three times the square of tlie first figure of the...
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Adams's Improved Arithmetic: Arithmetic, in which are Combined the Analytic ...

Daniel Adams - 1861 - 452 sider
...period, and write its root as a quotient in division. Subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained...
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Introduction to the National Arithmetic, on the Inductive System: Combining ...

Benjamin Greenleaf - 1861 - 338 sider
...in the left-hand period, and place its root on the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. RULE. — Separate the given number into as many periods as possible of three figures each,...
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The art and practical application of arithmetic, by J.& T. Flint

John Flint (inspector of schools.) - 1862 - 152 sider
...period, and write its cube root as the first figure of the root. Subtract its cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the part of the root found by 300 for a trial divisor ; divide the...
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New Elementary Algebra: in which the First Principles of Analysis are ...

Benjamin Greenleaf - 1863 - 338 sider
...the left-hand period, and place its root on the right ; subtract the cube of this root from the first period, and to the remainder bring down the next period for a dividend. At the left of the dividend write three times the square ofth* root already found, for a...
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New University Algebra: A Theoretical and Practical Treatise, Containing ...

Horatio Nelson Robinson - 1863 - 432 sider
...wríte its root for the first figure in the root sought ; subtract the square number from the left-hand period, and to the remainder bring down the next period for a dividend. III. At the left of the dividend write twice the first figure, of the root, for a trial divisor...
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - 1864 - 364 sider
...hand period, and write its root as the first term in the answer. Subtract the cube from the left hand period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found, considered as tens, by three for a trial divisor....
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A Written Arithmetic, for Common and High Schools: To which is Adapted a ...

George Augustus Walton - 1864 - 376 sider
...period, and write its root as the first term in the answer. Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. Take twice the root already found for a trial divisor ; rejecting the right hand figure of...
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Elements of Algebra: For Colleges, Schools, and Private Students, Bok 2

Joseph Ray - 1866 - 420 sider
...period, and place its root on the right, as in division. Subtract the cube of the root from the left period, and to the remainder bring down the next period for a dividend. 3d. Square the root already found, and multiply it by 3 for a trial divisor. Find how many...
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