| Enoch Lewis - 1844 - 228 sider
...two are termed the opposite extremes. Then Napier's rules are : 1. The rectangle of radius and the **sine of the middle part is equal to the rectangle of the** tangents of the adjacent extremes. 2. The rectangle of radius and the sine of the middle part is equal... | |
| Charles Davies - 1849 - 359 sider
...A=90°, we have sin B sin C cos a = R cos B cos C, or R cos a=cot B cot C; that is, radius into the **sine of the middle part is equal to the rectangle of the** tangent of the complement of B into the tangent of the complement of C, that is, to the rectangle of... | |
| Charles William Hackley - 1851 - 372 sider
...angled triangle may be expressed in the two following rules of Napier : 1. Radius multiplied by the **sine of the middle part is equal to the rectangle of the** tangents of the adjacent parts. 2. Radius multiplied by the sine of the middle part is equal to the... | |
| A. M. LEGENDRE - 1852
...sin B sin 0 cos a — cos B cos G, or, cos a — cot B cot (7; that is, radius, which is 1, into the **sine of the middle part is equal to the rectangle of the** tangent of the complement of B, into the tangent of the complement of (7, that is, to the rectangle... | |
| Thomas Jefferson, Henry Augustine Washington - 1854
...EXTREMES disjunct from the middle or EXTREMES DISJUNCT. He then laid down his catholic rule, to wit : " **The rectangle of the radius, and sine of the middle part, is equal to the rectangle of the** tangents of the two EXTREMES CONJUNCT, and to that of the cosines of the two EXTREMES DISJUNCT." And... | |
| Thomas Jefferson, Henry Augustine Washington - 1854
...EXTREMES disjunct from the middle or EXTREMES DISJUNCT. He then kid down his catholic rule, to wit : " **The rectangle of the radius, and sine of the middle part, is equal to the rectangle of the** tangents of the two EXTREMES CONJUNCT, and to that of the cosines of the two EXTREMES DISJUNCT." And... | |
| Charles Davies, Adrien Marie Legendre - 1854 - 432 sider
...which, it must be remembered, apply to the circular parts, as already defined. 1st. Radius inlo the **sine of the middle part is equal to the rectangle of the** tangents of the adjacent parts. 2d. Radius into the sine of the middle part is equal to the tidangle... | |
| Charles Davies - 1872 - 455 sider
...= tan (90°-a) tan b • ' • • (10.) Comparing these formulas with the figure, we see that, The **sine of the middle part is equal to the rectangle of the** tangents of the adjacent parts. These two rules are called Napier'a rales for Circular Parts, and they... | |
| 1874 - 455 sider
...tan (90°- a) tan 1> • • • • (10.) Comparing these formulas with the figure, wo seo that, The **sine of the middle part is equal to the rectangle of the** tangents of the adjacent parts. These two rules are called Napier's rules for Circular Parts, and they... | |
| William Guy Peck - 1876 - 366 sider
...(10) Comparing these formulas with the diagram, we see that the following rule is always true: 2d. The **sine of the middle part is equal to the rectangle of the** tangents of the adjacent parts. Discussion. 48. In applying Napier's rules, the required part is always... | |
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