 | Royal Military Academy, Woolwich - 1853 - 400 sider
...with the angles at the point F, which is the common vertex of the triangles ; that is, (2 Cor. 15. i.) together with four right angles. Therefore all the...twice as many right angles as the figure has sides. COR. 2. All the exterior angles of any rectilineal figure are together equal to four right angles.... | |
 | Euclid - 1853 - 176 sider
...internal angles, are equal to twice as many right angles as the figure has sides; but the internal angles, together with four right angles, are equal to twice as many right angles as the figure has sides (6); take away from both the internal angles, and the external angles remain, equal to four right angles... | |
 | Popular educator - 1854 - 922 sider
...all the angles of all the triangles thus formed are equal to all the angles of the figure (Conit.) ; therefore all the angles of the figure, together with...twice as many right angles as the figure has sides (Ax. 1). QED The demonstration of Euclid's Cor. II. viz. "that all the exterior angles of any rectilineal... | |
 | E. W. Beans - 1854 - 114 sider
...taken. If the entire survey has been made as above directed, the sum of all the internal angles will be equal to twice as many right angles as the figure has sides, diminished by four right angles. If this sum, as in practice will be likely to be the case, should... | |
 | Charles Davies - 1854 - 436 sider
...triangles in the figure ; that is, as many times as there are sides, less two. But this product is equal to twice as many right angles as the figure has sides, less four right angles. Cor. 1. The sum of the interior angles in a quadrilateral is equal to two right... | |
 | Euclides - 1855 - 270 sider
...all the angles of these triangles are equal to twice as many right angles as the figure has sides. Therefore all the angles of the figure together with...twice as many right angles as the figure has sides. СOR. 2. — All the exterior angles of any rectilineal figure, made by producing the sides successively... | |
 | William Mitchell Gillespie - 1855 - 436 sider
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. "... | |
 | Euclides - 1856 - 168 sider
...figure, together with the angles at the point F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the...twice as many right angles as the figure has sides. XVI. If two triangles have two sides of the one equal to two sides of the other, each to each, and... | |
 | Euclides - 1879 - 146 sider
...1) Therefore, if a side of any triangle, &c. QED Cor. 1. All the interior angles of any rectilineal figure together with four right angles, are equal...twice as many right angles as the figure has sides. For any figure ABCDE can be divided into as many As as it has sides, by drawing st. lines from a pt.... | |
 | Michael McDermott - 1879 - 552 sider
...and then mark the Y and telescope for future operations. 213. All the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. Example. Interior angles A, B, C, D, E, F = n° 4 right angles, 860 Sum = n° + 360° Namber of sides... | |
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Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 
