 | Oxford univ, local exams - 1885 - 358 sider
...to the squares described on the sides which contain the right angle. 7. Divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts may be equal to the square on the other part. 8. In a circle the angle in a semicircle is a right angle;... | |
 | Euclid, John Casey - 1885 - 340 sider
...together with four times the square on the line joining the points of bisection. 6. Divide a given line into two parts, so that the rectangle contained by the whole and one segment may be equal to any multiple of the square on the other segment. 7. If P be any point in the... | |
 | Euclides - 1885 - 340 sider
...together with lour times the square on the line joining the points of bisection. 6. Divide a given line into two parts, so that the rectangle contained by the whole and one segment may be equal to any multiple of the square on the other segment. 7. If P be any point in the... | |
 | George Bruce Halsted - 1886 - 394 sider
...in A, rectangle + AG* = GF* = GH* = AH* + AG*, by 243 J 112 PROBLEM II. 313. To divide a given sect into two parts so that the rectangle contained by...and one of the parts shall be equal to the square on the other part. Jf X GIVEN, the sect AB. REQUIRED, to find a point C such that rectangle AB,BC =... | |
 | Dalhousie University - 1887 - 206 sider
...between the points of section, is equal to the square on half the line. 10. Divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts may be equal to the square on the other part. 11. Tf a straight line touch a circle, and from the point... | |
 | Canada. Department of the Interior - 1888 - 756 sider
...triangle, and have one of its angles equal to a given rectilineal angle. 3. Divide a given straight line into two parts, so that the rectangle contained by...and one of the parts shall be equal to the square on the other part, and prove this algebraically also. 4. From a given circle cat off a segment which... | |
 | 1888 - 694 sider
...the third digit is twice the sum of the other two. Find the number. 5. Divide a line 20 inches long into two parts so that the rectangle contained by the whole and one part may be equal to the square of the other part. 6. Solve xs -f- ys = i8xy. x + y = 12. 7. The hypothenuse... | |
 | New Brunswick. Board of Education - 1889 - 1006 sider
...prove that the angle contained by these two sides is a right angle. -">. Divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts shall !«• i-qual to the square of the other part. Female Candidates for Class I will omit the 1st and... | |
 | E. J. Brooksmith - 1889 - 354 sider
...contained by the two parts, together with the square on the aforesaid part. 5. Divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts may be equal to the square on the other part. Describe a right-angled triangle sucl1 that the rectangle... | |
 | Queensland. Department of Public Instruction - 1890 - 532 sider
...construction only, necessary in each of the following problems: — (a) To divide a given straight line into two parts, so that the rectangle contained by...and one of the parts shall be equal to the square on the other part. (6) To describe a square that shall be equal to a given rectilineal figure. (11.14.)... | |
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To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part. 
