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" EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal... "
The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ... - Side 80
av Robert Simson - 1781 - 466 sider
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1867 - 400 sider
...{Construction. and DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; \Comtructvm. therefore the base EA is equal to the base EC, [I. 4. But EA was shewn...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1868 - 410 sider
...EB : (I. 6.) and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE, are equal to the two CD, DE, each to each...angle ADE is equal to the angle CDE ; for each of them is a right angle ; (constr.) therefore the base EA is equal to the base EC: (I. 4.) but EA was shewn...
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The Elements of Euclid, containing the first six books, with a selection of ...

Euclides - 1874
...to EB (I. 6) ; and because AD is equal to DC, and DE common to the triangles ADE, CDE; the two sides AD, DE, are equal to the two CD, DE, each to each...angle ADE is equal to the angle CDE, for each of them is a right angle (constr.) ; therefore 2. The base EA is equal to the base EC (I. 4) ; but EA was shown...
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Pure mathematics, Volum 1

Edward Atkins - 1874
...(Const.), and DE is common to the two triangles ADE, CDE, The two sides AD, DE are equal to the two sides CD, DE, each to each; And the angle ADE is equal to the angle CDE, for each of them is a right angle (Const.); Therefore the base EA is equal to the base EC (I. 4). But EA was shown to...
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Euclid's Elements of Geometry: Chiefly from the Text of Dr. Simson, with ...

Robert Potts - 1876 - 403 sider
...EB : (I. 6.) and because AD is equal to DC, and DE common to the triangle* ADE, CDE, the two sides AD, DE, are equal to the two CD, DE, each to each...ADE is equal to the angle CDE ', for each of them is a right angle ; (constr.) therefore the base EA is equal to the base EC: (I. 4.) but EA was shewn...
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Elements of geometry, based on Euclid, books i-iii

Edward Atkins - 1876 - 119 sider
...(Const.), and DE is common to the two triangles ADE, CDE, The two sides AD, DE are equal to the two sides CD, DE, each to each; And the angle ADE is equal to the angle CDE, for each of them is a right angle (Const.); I Therefore the base EA is equal to the base EC (I. 4). But EA was shewn...
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The Elements of Euclid for the Use of Schools and Colleges: With Notes, an ...

Isaac Todhunter - 1880 - 400 sider
...DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD,DE, each to each; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was...
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The Elements of geometry; or, The first six books, with the eleventh and ...

Euclides - 1881
...triangles ADE and CDE, the two sides AD and DE, are equal to the two sides CD and DE, each to each. But the angle ADE is -equal to the angle CDE, for each of them (Const.) is a right angle. Therefore the bage AE is equal (I 4) to the base fc. C. But AE was shown...
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The Elements of Euclid for the Use of Schools and Colleges: Comprising the ...

Euclid, Isaac Todhunter - 1883 - 400 sider
...[Construction. and DE is common to the two triangles ADE, CDE ; the two sides AD, DE are equal to the two sides CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; " [Construction. therefore the base EA is equal to the base EC. [I. 4. But EA was...
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Books 3-9

Euclid - 1908
...equal to DC, and DE is common, the two sides AD, DE are equal to the two sides CD, DE respectively ; and the angle ADE is equal to the angle CDE, for each is right ; therefore the base AE is equal to the base CE. But AE was proved equal to BE ; therefore...
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