 | Euclid - 1835 - 540 sider
...by BD, and because the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both; therefore Book IV. their... | |
 | Robert Simson - 1835 - 544 sider
...equal to KCF, and the right angle FHC equal to the right angle FKC; in the triangles FHC, FKC there are two angles of the one equal to two angles of the other, and the side FC, which is opposite to one of the equal angles in each, is common to both : therefore the other sides... | |
 | 1835 - 684 sider
...to А В С, and let the line EG meet DF, or DF produced in G. Then, because the triangles ABC, DEG have two angles of the one equal to two angles of the other, each to each, they are equiangular : therefore (31.) DE : EG ••AB: В С, but AB:BC::DE:EF: therefore... | |
 | John Playfair - 1836 - 148 sider
...therefore all the exterior angles are equal to four right angles. PROP. VI. THEOR. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, the triangles shall be equivalent. Let ABC, DEF be two... | |
 | 1836 - 488 sider
...greater base, shall be greater than the angle contained by the sides of the other. XXVI. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles,... | |
 | William Whewell - 1837 - 226 sider
...therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is, to RS. In the... | |
 | John Playfair - 1837 - 332 sider
...GNK, and the angles GMK, GMN are both right angles by construction ; wherefore, the triangles GMK. GMN have two angles of the one equal to two angles of the other, and they have also the side GM common, therefore they are equal(26. l.),andthe side KM is equal to the... | |
 | Andrew Bell - 1837 - 290 sider
...therefore the angle BAC is greater than the angle EDF. PROPOSITION XXVI. THEOREM. If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side ; namely, either the sides adjacent to the equal angles,... | |
 | A. Bell - 1837 - 180 sider
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
 | Charles Reiner - 1837 - 246 sider
...angles of the one is equal to the sum of the remaining two angles of the other. 2. If two triangles have two angles of the one equal to two angles of the other, each to each, the third angle of the one is equal to the third angle of the other ; that is, the triangles... | |
| |
If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
