| University of Madras - 1879 - 674 sider
...MA, I. Prove that all the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. II. Prove the proposition to which the following is a corollary : The difference of the squares on... | |
| Michael McDermott - 1879 - 552 sider
...for future operations. 213. All the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. Example. Interior angles A, B, C, D, E, F = n° 4 right angles, 860 Sum = n° + 360° Namber of sides... | |
| Benjamin Gratz Brown - 1879 - 68 sider
...in other words, all the interior angles of any rectilinear figure together with four right angles, are equal to twice as many right angles as the figure has sides. Again, parallelograms upon equal bases and with the same altitude are equal. Of all figures bounded... | |
| Moffatt and Paige - 1879 - 474 sider
...produced, etc. COR. 1. All the interior angles of any rectilineal f1gure, together with four right angles, are equal to twice as many right angles as the figure has sides. For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides, by... | |
| Euclides - 1879 - 146 sider
...&c. QED Cor. 1. All the interior angles of any rectilineal figure together with four right angles, are equal to twice as many right angles as the figure has sides. For any figure ABCDE can be divided into as many As as it has sides, by drawing st. lines from a pt.... | |
| Joseph Wollman - 1879 - 120 sider
...32. Corollary 1. — The interior angles of any rectilineal figure together with four right angles are equal to twice as many right angles as the figure has sides. The angles of a regular hexagon + 4 right angles = 12 right angles ; .-. The angles of a regular hexagon... | |
| Isaac Sharpless - 1879 - 282 sider
...But ACD+ACB = 2R; BAC+ABC+ACB = 2R. Corollary 1.—All the interior angles of a polygon are together equal to' twice as many right angles as the figure has sides, minus four right angles. Let ABODE be a polygon, and let n represent the number of its sides. Draw... | |
| Rolla Rouse - 1879 - 402 sider
...40 ... ... ... ... ... 103 The exterior and interior angles of an rectilineal figure, are together equal to twice as many right angles as the figure has sides, 41 ... 104 „ angles are together equal to four right angles, 42 ... ... ... ... „ The interior... | |
| W J. Dickinson - 1879 - 44 sider
...produced to meet, the angles formed by these lines, together with eight right angles, are together equal to twice as many right angles as the figure has sides. Same proposition. ABC is a triangle right-angled at A, and the angle B is double of the angle C. Show... | |
| Sir Norman Lockyer - 1880 - 668 sider
...Theorem XXVI. of the syllabus, that the interior angles of any polygon, together with four right angles, are equal to twice as many right angles as the figure has sides. In the new notation we would say that the sum of the interior angles of the polygon is equal to a number... | |
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