| 1836 - 472 sider
...base, shall be greater than the angle contained by the sides of the other. XXVI. If two triangles have **two angles of the one equal to two angles of the other,** each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles,... | |
| William Whewell - 1837 - 182 sider
...therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have **two angles of the one equal to two angles of the other ; and** the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is, to RS.... | |
| A. Bell - 1837 - 164 sider
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore **two angles of the one equal to two angles of the other, and** they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
| Charles Reiner - 1837 - 215 sider
...angles of the one is equal to the sum of the remaining two angles of the other. 2. If two triangles have **two angles of the one equal to two angles of the other,** each to each, the third angle of the one is equal to the third angle of the other ; that is, the triangles... | |
| Andrew Bell - 1837 - 240 sider
...therefore the angle BAC is greater than the angle EDF. PROPOSITION XXVI. THEOREM. If two triangles have **two angles of the one equal to two angles of the other,** each to each, and one side equal to one side ; namely, either the sides adjacent to the equal angles,... | |
| Euclides - 1838
...to KCF, and the right angle FHC equal to the right angle FKC ; therefore in the triangles FHC, FKC **there are two angles of the one equal to two angles of the other,** each to each ; and the side FC, which is opposite to one of the equal angles in each, is common to... | |
| Euclid, Robert Simson - 1838 - 416 sider
...by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have **two angles of the one equal to two angles of the other, and** the side BD, which is opposite to one of the equal angles in each is common to both ; therefore their... | |
| Thomas Kerigan - 1838
...the angle BCD, by the aforesaid proposition. And because the two triangles ADF and BCF have, thus, **two angles of the one equal to two angles of the other,** viz., the angle FAD to the angle FB C, and the angle AD F to the angle BCF; and the side AF of the... | |
| Euclides - 1841 - 351 sider
...and the right angle FCK is equal to the right angle FCL: therefore, in the two triangles FKC, FLC, **there are two angles of the one equal to two angles of the other,** each to each, and the side FC, which is adjacent to the equal angles in each, is common to both; therefore... | |
| Euclides - 1842
...by BD, and that the right angle BED is equal to the right angle BFD, the two triangles EBD, FBD have **two angles of the one equal to two angles of the other, and** the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore their... | |
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