 | Johann Odstrčil - 1879 - 96 sider
...— cos a, so erhält man eine andere Form der Fundamentalgleichung der sphärischen Trigonometrie cos A + cos B cos C — sin B sin C cos a. 28. Nimmt man dagegen die Vectortheile, so hat man « sin A = y cos B sin C + /3 cos 6' sin $ + F/37... | |
 | Carl Friedrich Gauss, Friedrich Wilhelm Bessel - 1880 - 644 sider
...findet : tang ß2 + tang C* — 2 tang B tang C cos a = sec /?z + sec C2 — 2 sec B sec C cos A oder cos A = cos B cos C + sin B sin C cos a usw Hieraus leitete ich, dadurch dass ich aus diesen Gleichungen sin «, sin 6, sin c bestimmte, sin... | |
 | Alexander Ross Clarke - 1880 - 390 sider
...put T\ e2 cos2 <£ = i : then on equating these values of BC2, we get after a slight reduction, 0 = 2 (cos a — cos b cos c— sin b sin c cos A') where H= 4bccoaA'—3c2-b2 = —a2- 2 accost, K- 4bccosA'—3b*—c2 = -a2 — 2at>cos C. Now put for... | |
 | 1881 - 566 sider
...wir aus der spliärischen Trigonometrie die vier Grundgleichungen: sin_a_sinj> ' siifä ~ süT/T 2) cos a — cos b cos c = sin b sin c cos a. 3) cos a -+- cos ß cos f — sin ß sin y cos a. 4) ctg a sin b = cos b cos f -+- sin f ctg a. Aus... | |
 | Carl Friedrich Gauß - 634 sider
...findet : tang B2 + tang C2 — 2 tang /, tang C cos a = sec B2 + scc C2 — 2 sec R scc C cos A oder cos A = cos B cos C -\- sin B sin C cos a usw Hieraus leitete ich , dadurch dass ich aus diesen Gleichungen sin a, sin b, sin e bestimmte, sin... | |
 | P. M. Holt, Ann K. S. Lambton, Bernard Lewis - 1977 - 582 sider
...(uniting the three sides and one angle of a spherical triangle) which has no equivalent in Ptolemy: cos a = cos b cos c — sin b sin c cos A A further advance was made with Abu'1-Wafa', and he was probably the first to demonstrate the sine... | |
 | André Caillemer, Catherine Le Cocq - 1983 - 272 sider
...tirer d'affaire en toutes circonstances, sans le secours d'imprimés qui risquent de faire défaut cos a = cos b cos c + sin b sin c cos A et : sin a sin b sin A sin B sin C Dans le triangle de position ces formules donnent : cos z = sin... | |
 | Berthold Horn - 1986 - 530 sider
...for the sides is cos a = cos 6 cos c + sin 6 sin c cos A, while the law of cosines for the angles is cos A = - cos B cos C + sin B sin C cos a. There are two more formulae in each case obtained by simultaneous cyclical permutation of a, 6, c and... | |
 | Marcel Berger - 2009 - 416 sider
...the cosine has absolute value less than 1 (remember that angles 0 and TT are not allowed by 18.6.2), we have cos a — cos b cos c sin b sin c which is equivalent to cos(6 + c) < cos a < cos(6 — c). For a,6,c 6 ]0, TT[ this implies a<6 + c<27r... | |
 | Jagat Narain Kapur - 1988 - 276 sider
...triangles are given by sin A sin B sin С .... —. = — — г = — : (25) sin a sin b sin c and cos a = cos b cos c + sin b sin c cos A (26) The point vertically above the observer is called his zenith and is denoted by Z. Thus OZ gives... | |
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A'B'C', and applying the law of cosines, we have cos a' = cos b' cos c' + sin b' sin c' cos A'. Remembering the relations a' = 180° -A, b' = 180° - B, etc. (this expression becomes cos A = — cos B cos C + sin B sin C cos a. 
