 | James M'Dowell - 1866 - 124 sider
...f- = tan - - - 1. 1 + tan|a \4 2/ If a + ft + 7 = ^, prove that cos a + cos /3 + cos 7 If an angle be divided into two equal parts and also into two unequal parts, the rectangle of the sines of the unequal parts, together with the square of the sine of the angle between the dividing... | |
 | Euclid, Isaac Todhunter - 1867 - 424 sider
...manifest, that parallellograms about the diameter of a square are likewise squares. PROPOSITION 5. THEOREM. If a straight line be divided into two equal parts...into two unequal parts, the rectangle contained by iht unequal parts, together with the square on the line between the points of section, is equal to... | |
 | Euclid, Isaac Todhunter - 1867 - 426 sider
...about the diameter of a square are likewise squares. PROPOSITION 5. THEOREM. If a straight line 1ie divided into two equal parts and also into two unequal parts, the rectangle contained l)y the unequal parts, together with the square on the line between the points of section, is equal... | |
 | 1868 - 344 sider
...explain how rectangular areas are represented by the product of two numerical symbols. SECTION VI. 1. If a straight line be divided into two equal parts, and also into two unequal parts, the rectal gle contained by the unequal parts, together with the square of the line between the points... | |
 | Robert Potts - 1868 - 434 sider
...= a' — m*, to each of these equals add m* ; .'. (a + m) (a — m) + m' = a*. That is, if a number be divided into two equal parts, and also into two unequal parts, the product of the unequal parts together with the square of half their difference, is equal to the square... | |
 | Horatio Nelson Robinson - 1868 - 276 sider
...be divided into two equal parts, and aha into two unequal parts, the rectangle contained by the two unequal parts together with the square of the line between the points of division, will be equivalent to the square on one half the line. Let AB be a line bisected in (7, and... | |
 | Euclides - 1870 - 270 sider
...&c. Psts. 2 and 3 ; 3. I. 10. I. To bisect a given finite st. line. Pst. 1. DEM. — 5. II. If a st. line be divided into two equal parts, and also into...rectangle contained by the unequal parts together with the squai e of the line between the points of section, equals the square of half the line. Def. 15 and... | |
 | Euclides - 1879 - 146 sider
...on the line intercepted between the other equal angle and the perpendicular. PROPOSITION V. THEOREM. If a straight line be divided into two equal parts,...contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the lint. Let AB be divided... | |
 | Edward Harri Mathews - 1879 - 94 sider
...right angle is equal to the square described on the sides which contain the right angle. Section IV. 1. If a straight line be divided into two equal parts...contained by the unequal parts together with the square on the line between the points of section, is equal to the square on half the line. Construct a rectangle... | |
 | Joseph Wollman - 1879 - 120 sider
...therefore they are between the same parallels (I. 39). Therefore DE is parallel to EC. QED SECTION IV. 1. If a straight line be divided into two equal parts,...contained by the unequal parts together with the square on the line between the points of section is equal to the square on half the line. Construct a rectangle... | |
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If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line. 
