| Nathan Fellowes Dupuis - 1889 - 294 sider
...the construction of 183° solves the problem, " To divide a given segment so that the rectangle on **the whole and one of the parts is equal to the rectangle** on the other part and the segment which is the sum of the whole and the first part." r i. Construct... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 515 sider
...= pq + pr= area ofreet. AB, AC + araz ofreet. AB, BC. PROPOSITION 3. If a straight line be divided **into any two parts, the rectangle contained by the...contained by the two parts, together with the square** on the aforesaid part Let AB be divided at C. Then rect. AB, BC=rect. AC, CB, with sq. on BC. On BC... | |
| Royal Military College, Sandhurst - 1890 - 132 sider
...factors a1, a2, a3, &c. II.— EUCLID AND TRIGONOMETRY. 1. Show that if a straight line be divided **into any two parts, the rectangle contained by the...contained by the two parts, together with the square** on the aforesaid part. To what algebraical formula does this proposition correspond ? 2. Describe a... | |
| Rupert Deakin - 1891 - 79 sider
...of the parts are together equal to the square on the. whole line. 3. If a straight line be divided **into any two parts, the rectangle contained by the...contained by the two parts, together with the square** on the aforesaid part. 4. If a straight line be divided into any two parts, the square on the whole... | |
| 1891
...9. If a straight line be divided into any two parts, then the rectangle .contained by the whole line **and one of the parts is equal to the rectangle contained by the two parts together with the square** on the aforesaid part. Prove this proposition. ALGEBRA (GRADE II. ACADEMY.) SECTION I. 1. Find the... | |
| Euclid - 1892 - 518 sider
...+ &) a + (a + &) I. PROPOSITION 3. THEOREM. If a straight line is divided into any two parts, tlie **rectangle contained by the whole and one of the parts is equal to the** square on that part together with the rectangle contained by the two parts. Let the straight line AB... | |
| N. F. DUPUIS, M.A., F.R.S.C. - 1894
...the construction of 183° solves the problem, " To divide a given segment so that the rectangle on **the whole and one of the parts is equal to the rectangle** on the other part and the segment which is the sum of the whole and the first part." 11. Construct... | |
| University of Sydney - 1898
...it. 3. If a straight line be divided into any two parts, the rectangle contained by the whole line **and one of the parts is equal to the rectangle contained by the two parts together with the square** on the aforesaid part. 4. If two straight lines cut one another within a circle, the rectangle contained... | |
| Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 304 sider
...then AB = a + b units ; and we have (« + bf PROPOSITION 3. THEOREM. If a straight line is divided **into any two parts, the rectangle contained by the whole and one of the parts is equal to the** square on that part together with the rectangle contained by the two parts. ACB Let the straight line... | |
| 1901
...is equal in area to the parallelogram AH. either В.— BOOK II. (6) If a straight line is divided **into any two parts, the rectangle contained by the whole and one of the parts is equal to the** square on that part, together with the rectangle contained by the two parts. If the point of division... | |
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