If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part. The Elements of Euclid - Side 41av Euclid - 1838 - 416 siderUten tilgangsbegrensning - Om denne boken
| Euclid, Sir Thomas Little Heath, Johan Ludvig Heiberg - 1908
...construction of this triangle depends upon n. n, or the problem of dividing a straight line so that **the rectangle contained by the whole and one of the parts is equal to the** square on the other part. This problem of course appears again in Eucl. vi. 30 as the problem of cutting... | |
| Cowley Oxon, dioc. school - 1860
...sides of it,the angle contained by these two sides is a right angle. 8. If a straight line be divided **into any two parts, the rectangle contained by the...by the two parts, together with the square of the** aforesaid part. 9. If a straight line be divided into two equal parts, and also into two unequal parts,... | |
| Education Department - 1879
...square on the base is less than the sum of the squares on the sides. 9. If a straight line be divided **into any two parts, the rectangle contained by the...contained by the two parts together with the square** on the aforesaid part. Show that this proposition in a particular case of proposition I. of the Second... | |
| Euclid
...construction of this triangle depends upon u. n, or the problem of dividing a straight line so that **the rectangle contained by the whole and one of the parts is equal to the** square on the other part. This problem of course appears again in Eucl. vi. 30 as the problem of cutting... | |
| Brian Lasater - 2008 - 600 sider
...is a variation on (a + b)(a - b) = a2 -- b2. Theorem 7 (II, 11) To cut a given straight line so that **the rectangle contained by the whole and one of the parts is equal to the** square of the other. Let the given line be AB. The problem is to find a point H on it so that AB x... | |
| |