 | William James Milne - 1907 - 616 sider
...Base Base 2. How is the area of a parallelogram found ? Then how is the area of a triangle found ? The area of a triangle is equal to half the product of its base and altitude, expressed in like units. WRITTEN EXERCISES 234. Find the areas of triangles having these... | |
 | Royal Military Academy, Woolwich - 1909 - 456 sider
...force required to extend the spring I centimetre. 4. Explain carefully the meaning of the rule that the area of a triangle is equal to half the product of its base and its altitude. State the rule in precise terms and establish its truth. 5. Construct a hexagon ABCDEF,... | |
 | Edward Rutledge Robbins - 1909 - 184 sider
...the product of one of these two sides and the projection of the other side upon that one. 378. The area of a triangle is equal to half the product of its bas» by its altitude. 444. Let С = circumference and R = radius. Then, С = 2 irR. PLANE TRIGONOMETRY... | |
 | William Herschel Bruce, Claude Carr Cody (Jr.) - 1910 - 286 sider
...equal altitudes are to each other as their bases. AREAS OF POLYGONS. PROPOSITION V. THEOREM. 425. The area of a triangle is equal to half the product of its base and altitude. AE Given the A ABC and its altitude CE. To prove AABC=±ABxCE. Proof. Construct the O... | |
 | George Albert Wentworth, David Eugene Smith - 1910 - 287 sider
...opposite sides cut one another into segments that are reciprocally proportional to each other. 53. The area of a triangle is equal to half the product of its perimeter by the radius of the inscribed circle. 54. The perimeter of a triangle is to one side as... | |
 | David Eugene Smith - 1911 - 360 sider
...be merely an approximation. The cutting of the paper is in every way more satisfactory. THEOREM. The area of a triangle is equal to half the product of its base by its altitude. Of course, the Greeks would never have used the wording of either of these two propositions.... | |
 | United States. Office of Education - 1911 - 1154 sider
...proportional between a secant from the same point and the external segment of the secant. 6. Prove that the area of a triangle is equal to half the product of Its base by Its altitude. Group III. 7. Find the area of a circle inscribed in an equilateral triangle whose side is... | |
 | 1911 - 1030 sider
...proportional between a secant from the same point and the external segment of the secant. 0. Prove that the area of a triangle is equal to half the product of Its base by its altitude. GROUP III. 7. Find the area of a circle inscribed in an equilateral triangle whose side is... | |
 | James Charles Byrnes, Julia Richman, John Storm Roberts - 1911 - 264 sider
...page 122. The triangle ADC equals one half of the , parallelogram AB CD', / 'herefore : -n RULE. The area of a triangle is equal to half the product of its base and altitude, expressed in like units. eg if the base is 4 ft. and the altitude 2 ft., the area is... | |
 | James Charles Byrnes, Julia Richman, John Storm Roberts - 1914 - 264 sider
...122. The triangle ADC equals one half of the parallelogram ABCD; therefore : ^ , , .D x*> RULE. The area of a triangle is equal to half the product of its base and altitude, expressed in like units. eg if the base is 4 ft. and the altitude 2 ft., the area is... | |
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The area of a triangle is equal to half the product of its base by its altitude. 
