 | George Lees - 1826 - 276 sider
...— — = - — 4, the numerator. The •* Jc 2 4 fraction sought is therefore -. EXERCISES. Ex. 1. It is required to divide the number 24 into two such parts, that twice the greater may exceed three times the less by 3. Ans. 15 and 9. Ex. 2. What number is that,... | |
 | Jeremiah Day - 1827 - 352 sider
...whose difference, sum, and product, are as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares, as 3 to 10. Ans. 18 and 6. 13. In a mixture of rum and brandy, the difference... | |
 | Henry Ottley - 1828 - 140 sider
...x2— 60z +900=36. (Extract the root,) and x— 30 =6, or x=36. Ans. the numbers are 24 and 36. 3. Divide the number 24 into two such parts, that their product shall be 35 times their difference. Let x=one part, then 24— x= the other, and 24 — 2x=the difference. Then... | |
 | Bourdon (M., Louis Pierre Marie) - 1831 - 446 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2Q. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 21. The sum of two numbers is 8, and the... | |
 | Charles Davies - 1835 - 378 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
 | 1838 - 372 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
 | Charles Davies - 1839 - 272 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their dif1 ference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | John D. Williams - 1840 - 634 sider
...then by the question (10— x)x=2l, or я?— 10z= — 21. Whence ж=5±(25— 21)= б±2=7 or 3. 13. It is required to divide the number 24 into two such...product shall be equal to 35 times their difference. Let x and у be the two parts ; then by the question we have „,. ж "т ^.~ ! Here z=24 — y, which... | |
 | Bewick Bridge - 1841 - 260 sider
...(x— yf=T2, or(*-y)2=4; .-. x— y=2.' Again, a? — 2xy+yf= 4, and 4xy = 96. a?+2xy+y2=100, Ex. 6. To divide the number 24 into two such parts, that their product shall be to the sum of their squares : : 3 : 10. 18 and 6. Ex. 7. There are two numbers which are to each other... | |
 | Charles Davies - 1842 - 368 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers is 8, and the... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
