 | 1853 - 380 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 4. It is required to divide the number 24 into two such parts, that theirv product may be equal to 35 times their difference. Ans. 10 and 14. 5. The sum of two numbers... | |
 | Popular educator - 1854 - 922 sider
...horse worth three times the 1st : what were the values of the two horses. Ans. £6, and £9. Prob. 25. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | 1855 - 424 sider
...are thoie, whose difference, sum and product, are as the numbers 2, 3 and 6, respectively ? Prob. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between... | |
 | Charles Davies - 1856 - 224 sider
...whence, by the rule, x = 50 ± VT96"= 50 ± 14 ; hence, ж = 64, x — 36, and у = 36, у = 64. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Let x and у denote the parts. From the conditions of the... | |
 | Charles Davies - 1859 - 324 sider
...13. Divide 100 into two such parts, that the sum of theii square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14 15. The stun of two numbers is 8, and the... | |
 | James B. Dodd - 1859 - 368 sider
...infinitely gfeat, to fulfil the conditions of the problem. - The problem is therefore impossible. EXAMPLE V. To divide the number 24 into two such parts, that their product shall be 150. If x represent one of the two parts, 24— z will represent the other and the equation will be... | |
 | Charles Davies - 1860 - 412 sider
...10. Divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 12. What two numbers are they, whose product... | |
 | Charles Davies - 1861 - 322 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | Horatio Nelson Robinson - 1861 - 372 sider
...| of yours, I can purchase the house. How much money had each of them? Ana. A had $160. B $120. 12. It is required to divide the number 24 into two such parts, mat the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | Charles Davies - 1864 - 316 sider
...Divide 100 into two such parts, that the sum of their Hquare roots may be 14. Ans. 64 and 36. 14. It i» required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
