 | George Roberts Perkins - 1848 - 234 sider
...and B's money which was $50 more than A's, was in trade 5 months ; what was A's stock 1 Ms. $100. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. What are the parts? Jins. 10 and 14. 15. A company at a... | |
 | Charles Davies - 1848 - 302 sider
...divide 100 into two such parts, that the sum 01 their square roots may be 14. ' Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the... | |
 | Horatio Nelson Robinson - 1848 - 354 sider
...of yours, I can purchase the house. How much money had each of them ? Ans. A had $160. B $120. 12. It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | Jeremiah Day, James Bates Thomson - 1848 - 264 sider
...those, whose difference, sum, and product, are as the numbers 2, 3 and 5, respectively I Prob. 12. Divide the number 24 into two such parts, that their product shall be to the sum of their squares as 3 to 10. Prob. 13. In a mixture of rum and brandy, the difference between... | |
 | James Wharton - 1848 - 164 sider
...numbers are as 2 to 3, to each of which if 6 be added, the sums will be as 4 to 5 ? Ans. 6 and 9. (58.) It is required to divide the number 24 into two such parts, that the quotient of the greater part divided by the less, may be to the quotient of the less part divided... | |
 | Charles William Hackley - 1849 - 534 sider
...To divide 100 into two such parts that the sum of their square roots nay be 14. Ans. 64 and 36. (19) It is required to divide the number 24 into two such parts that their roduct may be equal to 35 times their difference. Ans. -10 and 14. (20) The sum of two numbers is 8,... | |
 | Horatio Nelson Robinson - 1850 - 256 sider
...Divide the number a into two such parts, that the sum of the squares of those parts shall be b. Ans. 11. It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 12. The sum of two numbers is 8, and the... | |
 | John Bonnycastle - 1851 - 288 sider
...divide the number 40 into two such parts, that the sum of their squares shall be 818. Ans. 23 and 17. 3. It is required to divide the number 24 into two...equal to 35 times their difference. Ans. 10 and 14. 2. To'find a number such, that if you subtract it from 10, and then multiply the remainder by the number... | |
 | Joseph Ray - 1852 - 408 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. " Ans. 7 or 3. 8. It is required to divide the number 24 into two such...equal to 35 times their difference. Ans. 10 and 14. 9. Divide the number 346 into two such parts that the sum of their square roots shall be 26. Ans. II2... | |
 | Joseph Ray - 1848 - 250 sider
...of the symbol generally give both values of the unknown quantity, as in the following question. 4. Divide the number 24 into two such parts, that their product shall be 95. Let x= one of the parts ; then 24— x= the other. And x(24— x)=95 Or £'— 24x=— 95 Whence... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. Ans. 10 and 14. 
