Euclidian GeometryMacmillan, 1874 - 349 sider |
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Side 16
Francis Cuthbertson. PROPOSITION VII . It is always possible to draw a straight line perpendicular to a given straight line from a given point in the same . B D Let BC be the given straight line , and A the given point in it . Then from ...
Francis Cuthbertson. PROPOSITION VII . It is always possible to draw a straight line perpendicular to a given straight line from a given point in the same . B D Let BC be the given straight line , and A the given point in it . Then from ...
Side 17
... possible B let AF and AG be each of them 1 to BC . .. LS FAB , FAC are equal to one another , and also 4 s GAB , GAC are equal to one another , which is impossible . .. from a given point in a given straight line there cannot be drawn ...
... possible B let AF and AG be each of them 1 to BC . .. LS FAB , FAC are equal to one another , and also 4 s GAB , GAC are equal to one another , which is impossible . .. from a given point in a given straight line there cannot be drawn ...
Side 19
... possible , let BE be in the same straight line with BC ; .. LS ABC , ABE are together = two right angles ; ( 1.9 ) and are ..S ABC , ABD ; = .. LABE is L ABD , which is impossible . ( hyp . ) ... no other straight line than BD is in the ...
... possible , let BE be in the same straight line with BC ; .. LS ABC , ABE are together = two right angles ; ( 1.9 ) and are ..S ABC , ABD ; = .. LABE is L ABD , which is impossible . ( hyp . ) ... no other straight line than BD is in the ...
Side 20
Francis Cuthbertson. PROPOSITION XI . It is always possible to draw a perpendicular to a given straight line of an unlimited length from a given point without it . G E B Let A be any point without the straight line BC of unlimited length ...
Francis Cuthbertson. PROPOSITION XI . It is always possible to draw a perpendicular to a given straight line of an unlimited length from a given point without it . G E B Let A be any point without the straight line BC of unlimited length ...
Side 26
... possible , let a point in the path be without AB . Z F Join AQ , BQ . From AB cut off AE AQ , and BF = BQ . = Then to AE , BF may be applied the portions of the path AQ , BQ , meeting in some point Z , and thus forming a path AZB ...
... possible , let a point in the path be without AB . Z F Join AQ , BQ . From AB cut off AE AQ , and BF = BQ . = Then to AE , BF may be applied the portions of the path AQ , BQ , meeting in some point Z , and thus forming a path AZB ...
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Algebra Arithmetic base BEGINNERS Cambridge centre chord Christ's College circumference cloth Conic Sections Crown 8vo Describe a circle diagonals diameter divided ELEMENTARY TREATISE English equiangular equilateral Euclid Examples Extra fcap GEOMETRY given angle given circle given point given straight line Grammar greater H Let Hence inscribed intersecting isosceles triangle John's College Latin Let ABC line bisecting locus magnitudes Mathematical meet Owens College parallel parallelogram perimeter perpendicular plane PROBLEM produced Professor proportional PROPOSITION radius ratio rect rectangle rectangle contained rectilineal figure regular polygon render respectively revised rhombus right angles Schools Second Edition segment Similarly squares on AC straight line joining student tangent THEOREM TRIGONOMETRY twice rectangle twice the squares Uppingham School vertex
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Side 157 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth ; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth...
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