| Euclides - 1865
...draw a straight line AC, making any angle with AB, and in AC take any point D ; and take AC the same **multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to** CB. (i. 31.) Then AB shall be the part required to he out off. DEMONSTRATION Because ED is parallel... | |
| John Playfair - 1855 - 317 sider
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain **the part, which is to be cut off from it ; join BC, and draw DE parallel to it:** th«n AE is the part required to be cut off. Because CD is parallel to one of the sides of the triangle... | |
| Euclid, Isaac Todhunter - 1867 - 400 sider
...A draw a straight line AC, making any angle with AB; in AC tak e any point D, and take AC the same **multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it.** AE shall be the part required to be cut off. For, because ED is parallel to BC, one of the sides of... | |
| Euclid, Isaac Todhunter - 1867 - 400 sider
...point A draw a straight line AC, making any angle with AB; in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it.** AE shall be the part required to be cut off. For, because ED is parallel to BC, one of the sides of... | |
| Robert Potts - 1868 - 410 sider
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to** CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
| Euclides - 1876
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...from it ; join BC, and draw DE parallel to it : then** AK is the part required to be cut off. fa) VL 2. (6) V. 18. (c$ VD DEMONSTRATION. Because ED is parallel... | |
| Robert Potts - 1876 - 403 sider
...draw a straight line AC, making any angle with AB\ and in AC take any point D, and take ACtiie same **multiple of AD, that AB is of the part which is to be cut off from it ; join** BG, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel... | |
| Isaac Sharpless - 1879 - 266 sider
...any point D, and take AC so that it shall contain AD as many times as AB is to contain the part that **is to be cut off from it; join BC, and draw DE parallel to it; then AE is the part** to be cut off. Because ED is parallel to one of the sides of the triangle ABC (V. 2), CD : DA :: BE... | |
| Isaac Todhunter - 1880 - 400 sider
...point A draw a straight line AG, making any angle with AB; in AG take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it.** AE shall be the part required to be cut off. For, because ED is parallel to BC, [Construction. one... | |
| Euclides - 1881
...angle BAC, with AB. In AC take any point D, and make AC the same multiple of AD, that AB is of the part **to be cut off from it Join BC, and draw DE parallel to** E/-AB C B. The part AE is the part required to be cut off from AB. Because ED is parallel to BC, one... | |
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