 | Samuel Mecutchen, George Mornton Sayre - 1877 - 200 sider
...right triangle, AB is the hypotenuse, and AC, the perpendicular. To find the area of a triangle. RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be... | |
 | Joseph Ray - 1877 - 402 sider
...l« one-half the area of a parallelogram having the same base and altitude. 2d. When the three sides are given. Rule. — 1. From half the sum of the three sides take each side separately. 2. Multiply the half-sum and the three remainders together, and extract... | |
 | John Barter (of the science and art coll, Plymouth.) - 1877 - 328 sider
...completed ? EXERCISE CCXV. Having the three sides of any triangle given, to find its area. Rule. — From half the sum of the three sides subtract each side separately, multiply the half sum and the three remainders together, and the square root of the last product will... | |
 | William James Milne - 1877 - 402 sider
...product of the base by the altitude. When the three sides are given, the following is the rule: RULE. — From half the sum of the three sides subtract each side separately. Multiply together the half sum and the three remainders, and extract the square root of the product.... | |
 | Stoddard A. Felter, Samuel Ashbel Farrand - 1877 - 496 sider
...remainder. 27 — 24 = 3, 3d remainder. 27 X 15 X 9 X 3 = 10935. y 10935 = 104.57 sq. rds. area. RULE. — From half the sum of the three sides subtract each side separately ; then multiply the continued product of these remainders by half the sum of the sides, and extract... | |
 | Alfred Hiley - 1879 - 228 sider
...base by the height, and divide the product by 2. (2) To find the area, when the three sides are given. From half the sum of the three sides, subtract each side separately. Multiply the half sum and the three remainders together, and the square root of the product is the... | |
 | Edward Olney - 1879 - 392 sider
...altitude, or half of either multiplied into the oiher. 446. NOTE. — If the three sides only are given, from half the sum of the three sides subtract each side separately, multiply Hie half sum and these remainders together, and extract the square root of the product. The... | |
 | Samuel Mecutchen - 1880 - 292 sider
...supply the deficiency with ciphers. RULES IN MENSURATI0N. SURFACES. To find the area of a triangle. FROM half the sum of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will... | |
 | Thomas Liddell Ainsley - 1880 - 866 sider
...The area of a triangle may, however, be determined from its three sides by the following EULE LXV. From half the sum of the three sides, subtract each side separately ; then multiply the half sum and the three remainders together, and the square root of the latí product... | |
 | Samuel Mecutchen - 1880 - 262 sider
...supply the deficiency with ciphers. RULES IN MENSURATION. SURFACES. To find the area of a triangle. FROM half the sum of the three sides, subtract each side separately ; multiply the half sum and the three remainders together, and the square root of the product will... | |
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RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required. 
