 | William Frothingham Bradbury - 1882 - 416 sider
...from the vertex of the angle opposite the base to the base, or to the base produced ; as B D. 462. The area of a triangle is equal to half the product of its base and altitude. NOTE. For demonstration of the principles of Mensuration, Geometry must be consulted.... | |
 | George Anthony Hill - 1880 - 348 sider
...opposite sides ; then, since &ABC=% AB DC, and ABDC=AB x CE, therefore A ABC = ^ABy.CE. That is,— The area of a triangle is equal to half the product of its base by its altitude. Fig 125 Corollary. — All triangles having equal bases and equal altitudes are equivalent.... | |
 | William Frothingham Bradbury - 1880 - 260 sider
...Parallelograms having equal bases arid equal altitudes are equivalent. J THEOREM XVII. *.v. 43. The area of a triangle is equal to half the product of its base and altitude. Let BD be the altitude of the triangle ABC; then the area of ABC = \ AC X B D. Draw CE... | |
 | Evan Wilhelm Evans - 1884 - 170 sider
...on the same base, AB, and having the same altitude, CE (Cor. 2, Theo. XX), it A B"E follows that the area of a triangle is equal to half the product of its base by its altitude. Cor. 3.—Triangles on the same base or on equal bases, and of equal altitudes, have equal... | |
 | Evan Wilhelm Evans - 1884 - 242 sider
...a point, or center, equally distant from all the sides. EG— 6. Cor. 2. — Since the area of each triangle is equal to half the product of its base by its altitude, the area of all the triangles taken together is equal to half the product of the sum of their... | |
 | Charles Davies, Adrien Marie Legendre - 1885 - 538 sider
...other as their bases. If the bases are equal, they are to each other as their altitudes. Cor. 2. The area of a triangle is equal to half the product of its perimeter and the radius of the inscribed circle. For, let DEF be a circle inscribed in the triangle... | |
 | Charles Davies - 1886 - 352 sider
...Trapeioid*. THEOREM IX The area of a triangle is equal to half 11~. product of its base by its alt1tude. Let ABC be any triangle and CD its altitude : then will its area be equal to half the product of ABx CD. For, through B draw BE parallel to AC, and through C draw CE parallel to AB : we shall then... | |
 | William Chauvenet, William Elwood Byerly - 1887 - 331 sider
...V. The area of a parallelogram is equal to the product of its base and altitude. PROPOSITION VI. The area of a triangle is equal to half the product of its base and altitude. Corollary I. A triangle is equivalent to one-half of any parallelogram having the same... | |
 | James Wallace MacDonald - 1889 - 80 sider
...those having equal bases are to each other as their altitudes. Proposition IV. A Theorem. 239. The area of a triangle is equal to half the product of its base and altitude. COROLLARY. Triangles having the same base and altitude are equivalent. Proposition V.... | |
 | James Wallace MacDonald - 1894 - 76 sider
...those having equal bases are to each other as their altitudes. Proposition IV. A Theorem. 239. The area of a triangle is equal to half the product of its base and altitude. COROLLARY. Triangles having the same base and altitude are equivalent. Proposition V.... | |
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The area of a triangle is equal to half the product of its base by its altitude. 
