 | Charles Tayler - 1824 - 350 sider
...numbers is 10, and the sum of their squares is 52. What are the numbers ? ANS, 6 and 4. 8. Divide 89 into two such parts that the sum of their square roots may be 13. ANs. 64 and 25. 9. There are two numbers, whose difference' is to the difference of their square... | |
 | Peter Nicholson - 1825 - 1046 sider
...money, which was 50l. more than A.'s, was in trade five months ; what was A.'s stock ? Ans. 1 00l. 18. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. IQ. A and В distribute 12001. each among a certain number of persons ; A relieves 40 persons more... | |
 | Silvestre François Lacroix - 1825 - 394 sider
...given ; to find the numbers. Ans. a — V* — a* and a -f- Vb — &3 • 141. To divide the number 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 142. To find three such numbers, that the sum of the first and second multiplied into the third, may... | |
 | Silvestre François Lacroix - 1825 - 404 sider
...being given ; to find the numbers. Ans. a — v6 — o* and a + V6 — o» . 141. Tn divide the number 100 into two such parts, that the sum of their square roots may be 14. .ans. 64 and 36. 142. To find three such numbers, that the sum of the first and second multiplied into the third, may... | |
 | John Bonnycastle - 1825 - 336 sider
...from 10, and then multiply the remainder by the number itself, the product shall be 21. Ans. 7 or 3 3. It is required to divide the number 24 into two such parts, that their product shall be equal to 35 times their difference. Ans. 10 and 14 4. It is required to divide a line, of... | |
 | George Lees - 1826 - 276 sider
...— — = - — 4, the numerator. The •* Jc 2 4 fraction sought is therefore -. EXERCISES. Ex. 1. It is required to divide the number 24 into two such parts, that twice the greater may exceed three times the less by 3. Ans. 15 and 9. Ex. 2. What number is that,... | |
 | Bourdon (M., Louis Pierre Marie) - 1831 - 446 sider
...from 10, and multiply the remainder by the number itself, the product shall be 21. Ans. 1or 3. 19. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 2Q. It is required to divide the number 24 into two such parts, that their product may be equal to... | |
 | Silas Totten - 1836 - 360 sider
...their squares, may all be equal to one another. Ans. ^ ± J V5, and f ± \ V5. 17. Divide the number 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 18. Divide the number 40 into two such parts, that twice their product shall be equal to the cube of... | |
 | Charles Davies - 1839 - 272 sider
...To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such...that their product may be equal to 35 times their dif1 ference. Ans. 10 and 14. 15. The sum of two numbers is 8, and the sum of their cubes 152. What... | |
 | Charles Davies - 1839 - 264 sider
...whose difference, multiplied by the lesser, is equal to 12 ? Ans. 4 and 7, or § y^T and y -y/lT. 13. To divide 100 into two such parts, that the sum of their square roots may be 14. Ans. 64 and 36. 14. It is required to divide the number 24 into two such parts, that their product may be equal to... | |
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It is required to divide the number 24 into two such parts, that their product may be equal to 35 times their difference. 
